The recursive formula of the geometric sequence is given by option D; an = (1) × (5)^(n - 1) for n ≥ 1
<h3>How to determine recursive formula of a geometric sequence?</h3>
Given: 1, 5, 25, 125, 625, ...
= 5
an = a × r^(n - 1)
= 1 × 5^(n - 1)
an = (1) × (5)^(n - 1) for n ≥ 1
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Answer:
4x^2 + 8x + 4
4(x^2 + 2x + 1) - remove GCF of 4
4(x + 1)(x + 1) - factor
4(x + 1)^2 - collect like terms
Step-by-step explanation:
Then also expand it out by distributing:
21x^3 + 35x²
Form 1:
21x^3 + 35x² - unfactored
Form 2:
7x²(3x + 5) - factored with GCF of 7x² brought to the front
Update:
You could also multiply two binomials and make a quadratic.
Example:
(7x + 2)(3x + 5)
7x(3x + 5) + 2(3x + 5)
= 21x² + 35x + 6x + 10
= 21x² + 41x + 10
Slope=-5
as the line goes 5 down and 1 right
Answer:
Subtracting −7n+2 from 2n−1 is 9n - 3.
Step-by-step explanation:
As the expression given in the question be as follow.
−7n+2 and 2n - 1 .
Subtracted −7n+2 from 2n - 1 .
= 2n - 1 - (-7n + 2)
Open the bracket
= 2n - 1 + 7n - 2
Simplify the above
= 9n - 3
Therefore Subtracting −7n+2 from 2n−1 is 9n - 3.
Answer:
14..........................
