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Roman55 [17]
3 years ago
11

Which statement about 628,372 compared to 628,512 is true?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer:

It's the second one bc 500 is greater than 300 and it's the only reason why 628,512 is bigger than 628,372 .

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The perimeter of a square is 66.8 cm. What is the side length of the square?
Svetlanka [38]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
List the values that make up the domain of this relation.
balandron [24]

\bf (\stackrel{\downarrow }{5},3),(\stackrel{\downarrow }{2},-7),(\stackrel{\downarrow }{1},-8),(\stackrel{\downarrow }{8},3)\qquad \quad \stackrel{\textit{the domain is always the set of the 1st coordinate}}{(5,2,1,8)}

6 0
3 years ago
Ants have 6 legs. Elena and Andre write equations showing the proportional relationship between the number of ants, a, to the nu
Vlad [161]

Answer:

I agree with Elena

Step-by-step explanation:

Ants have 6 legs. Elena and Andre write equations showing the proportional relationship between the number of ants, a, to the number of ant legs, v.

Elena writes a = 6 times v

Andre writes v =1/6 times a.

Mathematically

The number of ants a is directly proportional to the number of legs

=a ∝ v

Because if

1 ant = 6 legs

2 ants = x legs

x = 6 legs × 2

x = 12 legs

The number of ants is directly proportional to the number of legs

Therefore, Elena is correct and Andre is wrong.

8 0
3 years ago
National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0
3 years ago
Which ordered pair is the solution to the system of equations?
tiny-mole [99]

Answer:

You can use Gaussian Elimination.

Double both sides of the first equation and add the second equation.

6x + 4y = 8

5x - 4y = 3

---------------

11x      = 11

x = 1

5 - 4y = 3

-4y = -2

y = 1/2

Step-by-step explanation:

7 0
3 years ago
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