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Juliette [100K]
3 years ago
11

Paul Aymes is a chrome plater at a local plant. If he plates 300 items or more,

Mathematics
1 answer:
Yuki888 [10]3 years ago
4 0
Creo que tienes que estar dividiendo
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The answer is C because it’s twice as long
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Please help i need now
Sunny_sXe [5.5K]

Answer:

8x10^-12

Step-by-step explanation:

Hope that helps.

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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

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3 0
1 year ago
Given f(x)= (4x+1)/3 solve for f^-1(3)
nirvana33 [79]
I hope this helps you

7 0
3 years ago
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If a1 = 9 and and an-1 - 5 then find the value of a6.
SCORPION-xisa [38]

Answer:

a1 = 6 and an = an-1 - 5

a2 = a2-1 - 5 = a1 - 5 = 1

a3 = a3-1 - 5 = a2 - 5 = -4, etc

Step-by-step explanation:

8 0
3 years ago
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