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2 years ago

(PLEASE HELP ASAP)

Mathematics

1 answer:

UNO [17]2 years ago

6 0

9514 1404 393

Answer:

A. 3×3

B. [0, 1, 5]

C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.

Step-by-step explanation:

A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.

This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...

A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)

Matrix A is 3×3.

B. The second row of A represents the second equation:

$0x_1+1x_2+5x_3=-1$

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.

C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)

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4+p over 14 = 1 need help

lukranit [14]

Answer:

p = 10

Step-by-step explanation:

In order to solve an equation we must isolate the variable we're solving for, p.

We can do this by undoing operations in the equation.

First, multiply both sides of the equation by 14.

$\frac{4+p}{14} * 14 = 1 *14$

This gives you 4 + p = 14

Then, you can subtract 4 from both sides:

4 - 4 + p = 14 - 4

p = 10

6 0

2 years ago

Anyone Can you please check the already done one, and the rest I just need help!!! please:

tia_tia [17]

Answer:

yes your math seems about right but wait for someone else to respond also because im not completely sure

Step-by-step explanation:

8 0

2 years ago

Please help!

Aleks [24]

Answer:

Probability of picking an even and then even number = $\frac{1}{6}$

Step-by-step explanation:

Probability of picking a card with even number,

P(even 1) = $\frac{\text{favorable outcomes}}{\text{Total outcomes}}$ = $\frac{\text{even cards}}{\text{Total number of cards}}$

= $\frac{2}{4}$

= $\frac{1}{2}$

Followed by picking a card which is even without putting the first card back.

So an even card is to be picked out of remaining 3 cards.

P(even 2) = $\frac{\text{favorable outcomes}}{\text{Total outcomes}}$

= $\frac{1}{3}$

Now probability of both events = P(even 1) × P(even 2)

= $\frac{1}{2}\times \frac{1}{3}$

= $\frac{1}{6}$

Therefore, probability of both the events will be $\frac{1}{6}$ .

5 0

3 years ago

Cos(−θ)=√3/3, sinθ<0

Delicious77 [7]

Answer:

$\sin\theta=-\frac{\sqrt{6}}{3}$

Step-by-step explanation:

The given trigonometric equation is $\cos(-\theta)=\frac{\sqrt{3} }{3}$ .

We can either use the Pythagorean identity or the right angle triangle to solve for $\sin\theta$ .

According to the Pythagorean identity,

$\cos^2\theta+\sin^2\theta=1$

Recall that, the cosine function is an even function, therefore

$\cos(-\theta)=\cos(\theta)$

$\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}$ .

We substitute this value in to the above Pythagorean identity to get;

$(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1$

$\Rightarrow \frac{3}{9}+\sin^2\theta=1$

$\Rightarrow \sin^2\theta=1-\frac{3}{9}$

$\Rightarrow \sin^2\theta=\frac{6}{9}$

$\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}$

$\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}$

But we were given that,

$\sin\theta\:$ , so we choose the negative value.

$\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}$

The correct answer is B

7 0

3 years ago

A conjecture and the two-column proof used to prove the conjecture are shown.

slavikrds [6]

given: s is the midpoint of rt

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8 0

2 years ago