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2 years ago

What is the area of this polygon? 40 cm2 18 cm2 16 cm2 24 cm2

Mathematics

2 answers:

Akimi4 [234]2 years ago

5 0

Answer:

40 cm 2 yes to Chou god cm,6 ja

tangare [24]2 years ago

4 0

Answer:

Step-by-step explanation:

I took the test

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What is wrong with the following equation: 4 + (10 / 5) = 6 - 2

ra1l [238]

This equation says that 6 = 4, which is incorrect. However, if there was no - 2 on the right side of the equation the answer would be correct as 6 = 6

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3 years ago

E-Z View cable company charges a flat rate of $40 per month for service and $4.95 for each pay per view movie. View the Best cha

Sliva [168]

The difference between the first company and the other is that the first charges $1 less per movie than the second , but charges $15 more than the second as well.
To awnser this problem and equal the charges in bth companies we just need to cancel out the $15 the first company charges more than the second.
As we pay more $1 each movie in the first , we would need to view 15 movies to equalize the charges from both companies :
x= 15 if we want to equalize the charges

f(x) = 4.95(15) + 40
f(x) = 74.25 + 40 = 114.25

g(x) = 5.95(15) + 25
g(x) = 89.25 + 25 = 114.25

Awnser: We would need to view 15 pay per view to equalize the bills from both companies

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3 years ago

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What is the probability of picking the most expensive car from a range of six new cars in a showroom?

Setler79 [48]

Answer:

since there are six cars and one choide

1/6

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2 years ago

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Geometry homework help :)

Harlamova29_29 [7]

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2 years ago

two planes start at 11 am from two airports 1800 miles apart, and fly toward each other at average rates of 200 and 250 miles pe

sweet [91]

Let the airports be airport A and airport B.

Let the plane with average rate 200mi/h leave airport A, at the same time the plane with average rate 250 mi/h leaves airport B.

Let |AC|=x, then |CB|=1800-x

Let the 2 planes pass each other at point C, after t hours.

Recall the formula: Distance= Rate*Time

so Time=Distance /Rate

(i) t= $\frac{x}{200}$ hours

(ii) t= $\frac{1800-x}{250}$ hours

equalizing:

$\frac{x}{200}=\frac{1800-x}{250}$

250x=200(1800-x)

2.5x=2(1800-x)

2.5x=3600-2x

2.5x+2x=3600

4.5x=3600

x=3600/4.5=800 (mi)

Having found x, now we can apply the formula distance=rate*time again to find the time t:

200*t=800

t=800/200=4 (hours)

we add 4 hours to 11 am, so the time will be 3pm

Answer: 3pm

3 0

3 years ago