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alukav5142 [94]
3 years ago
9

Someone please help me with this question

Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0

It would be in the order it is

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Physics
Andrej [43]

Answer:

a) Josef jogging from A to B;

i. speed = 2 m/s

ii. velocity = 2m/s

a) a) Josef jogging from A to C;

speed = 1.9 m/s

ii. velocity = 2.2 m/s

Step-by-step explanation:

One major difference between speed and velocity is that speed is a scalar quantity, while velocity is a vector quantity.

a) Josef jogging from A to B;

distance = 300 m

time = 2.5 seconds = 150 seconds

i. his average speed = \frac{distance}{time}

                               = \frac{300}{150}

                               = 2 m/s

ii. his average velocity = \frac{displacement}{time}

                               = \frac{300}{150}

                               = 2 m/s

b) Josef jogging from A to C,

distance = 300 + 100 = 400 m

time = 2.5 + 1 = 3.5 minutes

        = 210 seconds

i. his average speed = \frac{distance}{time}

                                  = \frac{400}{210}

                                  = 1.9 m/s

ii. his average velocity = \frac{\sqrt{V_{1} ^{2}   + V_{2} ^{2} } }{2}

V_{1} ^{2} = 4 m/s

V_{2} ^{2} = 1.9 m/s

his average velocity = \frac{\sqrt{4^{2} + 1.9^{2}  } }{2}

                                  = 2.2 m/s

5 0
3 years ago
Can anyone help me with this
Maksim231197 [3]

Answer:

D. 8x³ + 4x⁷ - 3x³ + 3x² - 2x + 9

Step-by-step explanation:

(8x⁸ - 9x³ + 3x² + 9) + (4x⁷ + 6x³ - 2x)

Apply distributive property to eliminate parentheses

8x⁸ - 9x³ + 3x² + 9 + 4x⁷ + 6x³ - 2x

Collect like terms

8x⁸ + 4x⁷ - 9x³ + 6x³ + 3x² - 2x + 9

8x³ + 4x⁷ - 3x³ + 3x² - 2x + 9

3 0
3 years ago
You are given m =0.4n - 2/3
inessss [21]

Answer:8.3

Step-by-step explanation:

4 0
3 years ago
What is 1.3 times 10 to the 15th power
svet-max [94.6K]
1.3 times 10 is 13 and 13 to the 15th power is 51185893014090760
5 0
3 years ago
Read 2 more answers
Please help ASAP!!!!!​
HACTEHA [7]
It’s D, y = 4.
have a good day :)
6 0
3 years ago
Read 2 more answers
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