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iris [78.8K]
3 years ago
11

Does anyone know how to do this problem? Thanks.

Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0
See picture for answer

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Please help immediately ​
Burka [1]

Answer:    f'(1)=\dfrac{4}{2y+1}

<u>Step-by-step explanation:</u>

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given:         0 = 2x² - xy - y²

Derivative:  0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

                   y'(2y + 1) = 4x

                   y'=\dfrac{4x}{2y+1}

\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}

8 0
2 years ago
A manager in a call center needs to determine how many agents to schedule next week.
lukranit [14]

Answer:

Number of calls expected in next week by manager = 7940

Average Number of calls that call center agent will attend in an hour =7 calls

It is also given that, Call center remain open for 10 hours 5 days a week.

Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week  ,Part time agents work 20 hours a week but are only on calls 17 hours per week .

⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940

⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940

Option A

⇒35×15×7+17×7×15

= 3675+1785

= 5460

Option B

⇒35 ×7×20+17×7×7

=4900 +833

= 5733

Option C

⇒35×20×7 +17×20×7

=4900+2380

=7280

Option D

⇒25 × 35×7+17×7×5

=6125 +595

=6720

Option E

⇒28×35×7+17×7×10

=6860+1190

=8050

Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.

7 0
2 years ago
Need some math help!!
BlackZzzverrR [31]
It's the second one.
7 0
2 years ago
Which Inequality is represented by the number line graph?
USPshnik [31]

Answer:

option C is your right answer

Step-by-step explanation:

have a nice day!!

8 0
2 years ago
O número 2021 tem resto 5 quando dividido pelo nmr 6, 7, 8, e pelo nmr 9. Quantos múmeros inteiros positivos menores do que 2021
Leokris [45]

336

Step-by-step explanation:

2021-5=2016÷6=336

8 0
2 years ago
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