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Pavel [41]
3 years ago
14

Divide. Give the exact answer, written as a decimal.

Mathematics
1 answer:
faust18 [17]3 years ago
7 0

Answer:

11.12

Hope this helps-

Step-by-step explanation:

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3x + x + 8 = 20 hhhhhhhhhhhssjsjjsjzjsjjsjsjsjsjsjsjsjsjsjjs
Flura [38]

Answer:

×=3

Step-by-step explanation:

3× + × + 8 = 20

4×= 12

divide 4 with 12 and it will be 3

8 0
3 years ago
Mai and Priya were on scooters. Mai traveled 15 meters in 6 seconds. Priya travels 22 meters in 10 seconds. Who was moving faste
nikklg [1K]

Answer:

Mai is moving faster than Priya.

Step-by-step explanation:

It is given that Mai traveled 15 meters in 6 seconds.

Speed=\frac{Distance}{Time}

The speed Mai is

\text{Speed of Mai}=\frac{15}{6}=2.5

Priya travels 22 meters in 10 seconds. Speed of Priya is

\text{Speed of Priya}=\frac{22}{10}=2.2

Since speed of Mai is more than the speed of Priya, therefore Mai is moving faster than Priya.

8 0
3 years ago
Your classmate wants you to check her work. She is working on a math question that asks her to determine the slope of a line giv
Hitman42 [59]
The answer of my classmate that the line has a positive slope is CORRECT. This is because the line is most likely to lean to the right. The slope can be calculated through the equation, 
                                    slope = rise / run = change in y / change in x
If both are negative, the slope is POSITIVE. 
5 0
3 years ago
Raise 7 to the 6th power, then add u to the result
nekit [7.7K]
I dont understand the question.
5 0
3 years ago
Please help solve the question in the picture! Find x
Mice21 [21]

Answer:

4√6

Step-by-step explanation:

On the below image, I labeled the 4 points A, B, C, and D. In this diagram, ΔABC is similar to ΔADB and ΔBDC.

Let's look at ∠C here, and find the ratio from the leg adjacent to ∠C and the hypotenuse in 2 triangles, ΔABC and ΔBDC. I chose these as they both share ∠C. You could do the same with ∠A, choosing ΔADB instead.

ΔABC: \frac{BC}{AC}=\frac{BC}{AD+DC}

ΔBDC: \frac{DC}{BC}

This is just the longer leg over the hypotenuse as said above. Because these triangles are similar, these ratios must be the same. We can write an equation to show that:

\frac{BC}{AD+DC}=\frac{DC}{BC}

In order to find BD, we first need to find either of the legs in ΔABC. I'll go for BC here as it looks like it'd be the easiest to solve for in this equation. Cross multiply:

\rightarrow \frac{BC}{AD+DC}=\frac{DC}{BC}\\\rightarrow BC\times BC = DC\times(AD+DC)\\\rightarrow (BC)^2=DC\times(AD+DC)

At this point, you can plug in the given values for AD and DC, then solve for BC.

\rightarrow (BC)^2=12\times(8+12)\\\rightarrow (BC)^2=12\times20\\\rightarrow (BC)^2=240\\\rightarrow BC=\sqrt{240}\\\rightarrow BC=\sqrt{2\times2\times2\times2\times3\times5}\\\rightarrow BC=4\sqrt{15}

Finally, you can use the pythagorean theorem to find x in ΔBDC.

\rightarrow 12^2+x^2=(4\sqrt{15})^2\\\rightarrow 144+x^2=16\times15\\\rightarrow 144+x^2=240\\\rightarrow x^2=240-144\\\rightarrow x^2=96\\\rightarrow x=\sqrt{96}\\\rightarrow x=\sqrt{2\times2\times2\times2\times2\times3}\\\rightarrow x=4\sqrt{6}

8 0
3 years ago
Read 2 more answers
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