<span>The problem is to calculate the angles of the triangle. However, it is not clear which angle you have to calculate, so we are going to calculate all of them
</span>
we know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]
a=12.5
b=15
c=11
so
cos C=[a²+b²-c²]/[2*a*b]---> cos C=[12.5²+15²-11²]/[2*12.5*15]
cos C=0.694------------> C=arc cos (0.694)-----> C=46.05°-----> C=46.1°
applying the law of sines calculate angle B
15 sin B=11/sin 46.1-----> 15*sin 46.1=11*sin B----> sin B=15*sin 46.1/11
sin B=15*sin 46.1/11-----> sin B=0.9826----> B=arc sin (0.9826)
B=79.3°
calculate angle A
A+B+C=180------> A=180-B-C-----> A=180-79.3-46.1----> A=54.6°
the angles of the triangle are
A=54.6°
B=79.3°
C=46.1°
Answer:
57 + x³
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
The equation becomes 9 *4 * 1/6. Then you simplify and get 6.
Please mark me as Brainliest if it is correct, thx.
Answer:
19
Step-by-step explanation:
by replacing x and y with their given values ,
we get :-
=》2x + 7y - 10
=》(2 × 4) + (7 × 3) - 10
=》8 + 21 - 10
=》29 - 10
=》19
