Given: An Isosceles trapezoid EFGH in which EF =GH
To prove: ΔFHE ≅ ΔGEH
Proof: In Isosceles trapezoid EFGH, Considering two triangles ΔFHE and ΔGEH
1. FE ≅ G H → [ Given]
2. ∠H = ∠E
→ Draw GM⊥HE and FN ⊥EH, and In Δ GMH and ΔFNE,
GH=FE [Given]
∠M+∠N=180° so GM║FN and GF║EH, So GFMN is a rectangle.]
∴ GM =FN [opposite sides of rectangle]
∠GMH = ∠FNE [ Each being 90°]
Δ GMH ≅ ΔFNE [ Right hand side congruency]
→∠H =∠E [CPCT]
→ Side EH is common i.e EH ≅ EH .
→ΔFHE ≅ ΔGEH. [SAS]
Given:
The functions are
To find:
The value of g(f(0)).
Solution:
We have,
Putting x=0, we get
Now,
![[\because f(0)=0]](https://tex.z-dn.net/?f=%5B%5Cbecause%20f%280%29%3D0%5D)
![[\because g(x)=x+6]](https://tex.z-dn.net/?f=%5B%5Cbecause%20g%28x%29%3Dx%2B6%5D)
Therefore, the value of g(f(0)) is 6 and the correct option is B.
Answer:
15
Step-by-step explanation:
you take the area and divide it by 6 since a cube has 6 sides then you find the square root of the number you got which is 15
1350÷6=225
=15
Answer:
Please link a picture so i can see what you need help with.
Thanks!!!
Answer:
Part A - he will need 2 cups of sugar
Part B - 12 : 6 : 3
Step-by-step explanation:
Part A :
8 divided by 4 is 2
Part B :
Multiply all the numbers by 3
Hope this helped! :)
