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gtnhenbr [62]
3 years ago
12

A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

other features. The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 39 months and a standard deviation of 10 months. Using the 68-95-99.7 rule, what is the approximate percentage of cars that remain in service between 59 and 69 months? Do not enter the percent symbol.
Mathematics
1 answer:
vredina [299]3 years ago
8 0

Answer:

2.35%

Step-by-step explanation:

Mean number of months (M) = 39 months

Standard deviation (S) = 10 months

According to the 68-95-99.7 rule, 95% of the data is comprised within two standard deviations of the mean (39-20 to 39+20 months), while 99.7% of the data is comprised within two standard deviations of the mean (39-30 to 39+30 months).

Therefore, the percentage of cars still in service from 59 to 69 months is:

P_{59\ to\ 69}=\frac{P_{9\ to\ 69}-P_{19\ to\ 59}}{2} \\P_{59\ to\ 69}=\frac{99.7-95}{2}\\P_{59\ to\ 69}=2.35\%

The approximate percentage of cars that remain in service between 59 and 69 months is 2.35%.

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<em>Disclaimer</em><em>:</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>actually</em><em> </em><em>x</em><em> </em><em>(</em><em>or</em><em> </em><em>y</em><em>)</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>of</em><em> </em><em>two</em><em>,</em><em> </em><em>but</em><em> </em><em>a</em><em> </em><em>way</em><em> </em><em>to</em><em> </em><em>distinguish</em><em> </em><em>one</em><em> </em><em>x</em><em> </em><em>(</em><em>or</em><em> </em><em>y</em><em>)</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>other</em><em>.</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>label</em><em> </em><em>of</em><em> </em><em>sorts</em><em>.</em>

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