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rewona [7]
2 years ago
6

The zeros of a quadratic function are -7 and 3. Which of the following could be the function? Select all that apply.

Mathematics
1 answer:
vladimir2022 [97]2 years ago
5 0

Answer:

Hello! Your answer would be, A)F(x)=2x^2-8x-42

Step-by-step explanation:

Hope I helped! Brainiest plz!♥ Have a nice afternoon. Hope you make a 100%! -Amelia

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Which statement correctly describes this expression?<br> 2m^3 - 11
Nady [450]

Answer:

<h2>D</h2>

The cube of twice a number decreased by 11

6 0
2 years ago
Estimate how many times larger (1.9) x 10⁻⁸ is than (4.2) x 10⁻¹³ ????
Igoryamba

Answer:

1.9 x 10=19

4.2x10=42

Now just find out how to multiply 19 -8 times and how to multiply 42, -13 times.

Step-by-step explanation:

hope this helps if not sorry

8 0
2 years ago
Read 2 more answers
Plz answer both if you can
Harlamova29_29 [7]
I hope this helps you



130+x-5+x-35+x+30+75=360


3x=360-195


3x=165


x=55


m (B)=55-5=50
7 0
2 years ago
help please <br><br> No links
11Alexandr11 [23.1K]

Answer:

62-0.75x8

Step-by-step explanation

$6=discount

8 tickets

Total=62.00

0.75 multiplied by 8= 6

62-6=56

56 is before the discount

Equation would be 62-0.75x8

8 0
2 years ago
Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

  • 2 in a unique way (1+1)
  • 3 in two possible ways (1+2, 2+1)
  • 4 in three possible ways
  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0
2 years ago
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