Answer:
The analytical molar concentration is 0,04743M
The equilibrium concentrations are HA = 0,01281M; H⁺ and A⁻ = 0,03462M
Explanation:
The analytical molar concentrations is:
155mg ≡ 0,155g÷163,4g/mol = 9,486x10⁻⁴ moles
9,486x10⁻⁴ moles ÷ 0,020L = <em>0,04743 M</em>
The trichloroacetic acid [HA] dissociates in water in a 73%, thus:
HA ⇄ H⁺ + A⁻
The equilibrium concentrations are:
HA = 0,04743M ×(100-73)% = 0,01281M
H⁺ and A⁻ = 0,04743M ×73% = 0,03462M
I hope it helps!
