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3 years ago

13

What is the daily cost of incandescent lamp

1 answer:

Grace [21]3 years ago

6 0

I think the answer is $0.03

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Why the mixture of bromine and ethane is discoloured when left in the sun

DENIUS [597]

Answer:

In the presence of UV light, ethane will react with bromine in a substitution reaction. UV light is the condition under which the reaction will occur so it is written above the arrow in the chemical equation. As the reaction proceeds, the intensity of the re-brown colour of the bromine water decreases.

8 0

2 years ago

Read 2 more answers

A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t

Elan Coil [88]

Answer:

A. endothermic.

A. Yes, absorbed.

Explanation:

Let's consider the following thermochemical equation.

2 HgO(s) ⇒ 2 Hg(l) + O₂(g) ΔH = 182 kJ

The enthalpy of the reaction is positive (ΔH > 0), which means that the reaction is endothermic.

182 kJ are absorbed when 2 moles of HgO react (molar mass 216.59 g/mol). The heat absorbed when 72.8 g of HgO react is:

$72.8g.\frac{1mol}{216.59g} .\frac{182kJ}{2mol} =30.6kJ/mol$

6 0

3 years ago

How many moles are in 25.90 grams of NaCl

inessss [21]

Answer:

0.44316859040048207mol

Explanation:

7 0

3 years ago

What is the ROUNDED atomic number for this elements?

denis-greek [22]

Sodium/Atomic number

11

Gold/Atomic number

79
Potassium/Atomic number

19

Silicon/Atomic number

14

8 0

3 years ago

Now they feel it is best to have you identify an unknown gas based on its properties. Suppose 0.508 g of a gas occupies a volume

pishuonlain [190]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

mass = 0.508 g, Volume = 0.175 L

Temperature = (25 + 273) K = 298 K, P = 1 atm

As per the ideal gas law, PV = nRT.

where, n = no. of moles = $\frac{mass}{\text{molar mass}}$

Hence, putting all the given values into the ideal gas equation as follows.

PV = $\frac{mass}{\text{molar mass}} \times RT$

1 atm \times 0.175 L = $\frac{0.508 g}{\text{molar mass}} \times 0.0821 L atm/ K mol \times 298 K$

= 71.02 g

As the molar mass of a chlorine atom is 35.4 g/mol and it exists as a gas. So, molar mass of $Cl_{2}$ is 70.8 g/mol or 71 g/mol (approx).

Thus, we can conclude that the gas is most likely chlorine.

4 0

3 years ago