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STALIN [3.7K]
3 years ago
13

What is the daily cost of incandescent lamp

Chemistry
1 answer:
Grace [21]3 years ago
6 0
I think the answer is $0.03
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What determines the average kinetic energy of the particles in a gas?
jolli1 [7]

Answer:

D

The temperature.

Explanation:

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3 years ago
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How many atoms are in 4 mol Zn?
Brut [27]
To covert from moles to atoms times the number of moles by Avogadro's Number (6.022×10²³)

4.0 × 6.022×10²³ = 2.4088×10^24
6 0
3 years ago
Balance the equation ____Mg+_____HNO3=____Mg(NO3)2+H2
Arturiano [62]

Explanation:

2Mg⁺ 2HNO₃ = Mg(NO₃)₂ + H₂

7 0
2 years ago
The solubility of carbon dioxide in water is 0.161 g CO2in 100 mL of water at 20ºC and 1.00 atmCO2. A soft drink is carbonated w
Sedbober [7]

<u>Answer:</u> The solubility of carbon dioxide at 5.50 atm is 0.886g/100mL

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of carbon dioxide

C_2\text{ and }p_2 are the final concentration and partial pressure of carbon dioxide

We are given:

C_1=0.161g/100mL\\p_1=1.00atm\\C_2=?\\p_2=5.50atm

Putting values in above equation, we get:

\frac{0.161g/100mL}{C_2}=\frac{1.00atm}{5.50atm}\\\\C_2=\frac{0.161g/100mL\times 5.50atm}{1.00atm}=0.886g/100mL

Hence, the solubility of carbon dioxide at 5.50 atm is 0.886g/100mL

4 0
3 years ago
How many grams of solute are dissolved in 125.0 mL of 5.00 M NaCl (MM = 58.45)?
Nookie1986 [14]

Answer: 36.53g

Explanation:

First we need to find the amount of NaCl that dissolves in 1L of the solution that produced 5M of NaCl

Molarity = 5M

MM of NaCl = 58.45

Molarity = Mass conc (g/L) / MM

Mass conc. (g/L) of NaCl = Molarity x MM

= 5 x 58.45 = 292.25g

Next, we need to find the amount that will dissolve in 125mL(i.e 0.125L)

From the calculations above,

292.25g of NaCl dissolved in 1L

Therefore Xg of NaCl will dissolve in 0.125L of the solution i.e

Xg of NaCl = 292.25 x 0.125 = 36.53g.

Therefore 36.53g of NaCl will dissolve in 125mL of the solution

5 0
3 years ago
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