The name of the following molecular compound: P203

What force in liquids causes surface tension? covalent forces intermolecular forces intramolecular forces ionic forces.

artcher [175]

Answer:

Intermolecular forces

Explanation:

Intermolecular forces cause surface tension.

Source info:
"Surface tension, capillary action, and viscosity are unique properties of liquids that depend on the nature of intermolecular interactions."

(11.S: Liquids and Intermolecular Forces (Summary)https://chem.libretexts.org )

7 0

2 years ago

Please help<br><br>Differentiate between the three systems of rearing pigs.

natulia [17]

this is ur answer

plzzz mark me as brainliest

5 0

3 years ago

An ideal gas is brought through an isothermal compression process. The 3.00 mol of gas goes from an initial volume of 261.6×10−6

Eduardwww [97]

Answer : The temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

Explanation : Given,

Initial volume of gas = $261.6\times 10^{-6}m^3$

Final volume of the gas = $138.2\times 10^{-6}m^3$

Heat released = -9340 J

First we have to calculate the temperature of the gas.

According to the question, this is the case of isothermal reversible compression of gas.

As per first law of thermodynamic,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

$q=-w$

Thus, w = -q = 9340 J

The expression used for work done will be,

$w=nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = 9340 J

n = number of moles of gas = 3 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = ?

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

Now put all the given values in the above formula, we get the temperature of the gas.

$9340J=3mole\times 8.314J/moleK\times T\times \ln (\frac{261.6\times 10^{-6}m^3}{138.2\times 10^{-6}m^3})$

$T=586.83K$

Now we have to calculate the final pressure of the gas by using ideal gas equation.

$PV=nRT$

where,

P = final pressure of gas = ?

V = final volume of gas = $138.2\times 10^{-6}m^3=138.2\times 10^{-9}L$

T = temperature of gas = 586.83 K

n = number of moles of gas = 3 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get:

$P\times (138.2\times 10^{-9}L)=3mole\times (0.0821L.atm/mole.K)\times (586.83K)$

$P=1.046\times 10^{9}atm$

Therefore, the temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

6 0

3 years ago

Iodine-131 is a radioactive isotope with a half-life of 8 days. how many grams of a 64 g sample of iodine-131 will remain at the

icang [17]

At the end of 24 days, there will only be 16 g.

7 0

3 years ago

6. The gas in a steel cylinder is at 55 °C and a pressure of 965 mmHg. What would be the temperature,

ohaa [14]

Answer:

91.4°C

Explanation:

Gay - Lussac Law => T ∝ P => T = kP => k = T/P with volume (V) and mass (n) constant.

For two different Temperature (T)-Pressure (P) conditions

k₁ = k₂ => T₁/P₁ = T₂/P₂ => T₂ = T₁(P₂/P₁)

T₁ = 55°C = (55 + 273)K = 328K

P₁ = 965 mmHg

T₂ = ?

P₂ = 850 mmHg

T₂ = T₁(P₂/P₁) = 328K(850 mmHg/965 mmHg) = 364K = (364 - 273)°C = 91.4°C

6 0

2 years ago