Igneous rock forms from heat and pressure
To solve this given problem, we can use the equation below:
ΔG=ΔH - T*ΔS
We are information and values are given and can be used in solving the ΔG of this particular reaction.
ΔH=-99.84kJ
ΔS=-16.80 J/K
T=298K
ΔG=(-99.84kJ)-(298K*-16.80J/K)
ΔG=-94.83kJ
The answer for ΔG is -94.83kJ.
Yes...yes it does describe an exothermic reaction
Answer:
1.5x10²² particulates
Explanation:
Assuming ideal behaviour, we can solve this problem by using the <em>PV=nRT </em>formula, where:
- V = 250 mL ⇒ 250 / 1000 = 0.250 L
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 15 °C ⇒ 15 + 273 = 288 K
We <u>input the given data</u>:
- 2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K
And <u>solve for n</u>:
Finally we <u>calculate how many particulates are there in 0.025 moles</u>, using <em>Avogadro's number</em>:
- 0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates
North Pole ,land is the answer
