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2 years ago

Which statement describes how heat flows from the coffee to the part of the spoon in the coffee?

Chemistry

2 answers:

lozanna [386]2 years ago

8 0

Answer:

Heat flows from the coffee to the spoon through conduction

Explanation: I took did the lab assignment

Neporo4naja [7]2 years ago

5 0

Answer:

<h2>C.Heat flows from the coffee to the spoon through conduction.</h2>

E 2020

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The combustion of gasoline produces carbon dioxide and water. Assume gasoline to be pure octane (C8H18) and calculate the mass (

Mariulka [41]

Answer:

3.09kg

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol

Mass of C8H18 from the balanced equation = 2 x 114 = 228g

Converting 228g of C8H18 to kg, we obtained:

228/1000 = 0.228kg

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 16 x 44 = 704g

Converting 704g of CO2 to kg, we obtained:

704/1000 = 0.704kg

From the equation,

0.228kg of C8H18 produced 0.704kg of CO2.

Therefore, 1kg of C8H18 will produce = 0.704/0.228 = 3.09kg of CO2

6 0

2 years ago

Different types of cells within an organism_______.

Olin [163]

Answer:

B.)

Explanation:

Anwser is b yw c:

6 0

2 years ago

Read 2 more answers

In the laboratory a student determines the specific heat of a metal. She heats 19.6 grams of zinc to 98.37°C and then drops it i

fgiga [73]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

Step 1: Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc = 98.37 °C

Initial temperature of water = 24.16 °C

Final temperature of water (and zinc) = 25.70 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate Specific heat of zinc

Heat lost by zinc = heat won by water

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

Qzinc = -Qwater

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

7 0

2 years ago

How many moles of hydrogen gas are produced when 3.8 moles of HCI are reacted? O 1.9 mol

igor_vitrenko [27]

1.9 mol H2.
3.8 mol HCl * (1 mol H2 / 2 mol HCl) = 1.9 mol H2

3 0

2 years ago

Considering what you now know about charles law make a prediction based on the follwong sittutaion what would happen to the volu

nikklg [1K]

Answer:

The volume of the gas got doubled.

Explanation:

Charle's law states that the volume of an ideal gas is direclty proportional to the absolute temperature.

Thus, V ∝ T

Or,

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

If the bottle is heated to the double of the temperature, the volume of the gas also gets doubled.

3 0

2 years ago