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2 years ago

Which statement describes how heat flows from the coffee to the part of the spoon in the coffee?

Chemistry

2 answers:

lozanna [386]2 years ago

8 0

Answer:

Heat flows from the coffee to the spoon through conduction

Explanation: I took did the lab assignment

Neporo4naja [7]2 years ago

5 0

Answer:

<h2><u>C.Heat flows from the coffee to the spoon through conduction.</u></h2>

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Which is false HCI + CaCO3

tekilochka [14]

Answer:

CaCO3 is false

Explanation:

Because HCl is hydrongen chloride

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2 years ago

A solution that has a large amount of dissolved solute is called

kvasek [131]

Answer: It is an unsaturated solution

Explanation: This is because it has more solute than a normal solution.

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2 years ago

When 16.35 moles of SI reacts with 11.26 moles of N2, how many moles of SI3N4 are formed

Allushta [10]

Answer:

5.450 mol Si₃N₄

Explanation:

Step 1: Write the balanced equation

3 Si + 2 N₂ ⇒ Si₃N₄

Step 2: Establish the theoretical molar ratio between the reactants

The theoretical molar ratio of Si to N₂ is 3:2 = 1.5:1.

Step 3: Establish the experimental molar ratio between the reactants

The experimental molar ratio of Si to N₂ is 16.35:11.26 = 1.45:1. Comparing both molar ratios, we can see that Si is the limiting reactant.

Step 4: Calculate the moles of Si₃N₄ produced from 16.35 moles of Si

The molar ratio of Si to Si₃N₄ is 3:1.

16.35 mol Si × 1 mol Si₃N₄/3 mol Si = 5.450 mol Si₃N₄

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2 years ago

Which type of compound usually has higher melting points: ionic compounds or covalent compounds?

faltersainse [42]

Ionic bonds generally have higher melting points due to stronger electrostatic interactions.

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2 years ago

Calculate the ph of the resulting solution if 34.0 ml of 0.340 m hcl(aq is added to

anyanavicka [17]

According to the reaction equation:

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

a) Part 1):

first, we need to get moles HCl = molarity * volume

= 0.34m * 0.034

= 0.01156 mol

then, we need moles of NaOH = molarity * volume

= 0.34 * 0.039

= 0.01326 mol

when NaOH excess:

∴ NaOH remaining = 0.01326 - 0.01156

= 0.0017 mol

when the total volume = 0.039 + 0.034

= 0.073 L

∴[OH] = moles / total volume

= 0.0017mol / 0.073 L

= 0.0233 M

∴ POH = -㏒[OH-]

= -㏒0.0233

= 1.63

∴ PH = 14- 1.63

= 12.37

b) part 2:

as we got moles HCl = molarity * volume

= 0.34 * 0.034

= 0.01156 mol

then moles NaOH = molarity * volume

= 0.39 * 0.044

= 0.01716 mol

NaOH remaining = 0.01716 - 0.01156

= 0.0056 mol

when the total volume = 0.034 + 0.044

= 0.078 L
∴[OH-] = 0.0056 / 0.078

= 0.0718 M

∴ POH = -㏒[OH-]

= -㏒0.0718

= 1.14

∴PH = 14 - POH

= 14 -POH

= 14 - 1.14

= 12.86

8 0

2 years ago

Read 2 more answers