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stich3 [128]
3 years ago
14

Whats the answer to this plz help​

Mathematics
2 answers:
lozanna [386]3 years ago
4 0

Answer:

a1 = 1

an = an-1 * -5

Step-by-step explanation:

Reptile [31]3 years ago
3 0
I’ve attached my work...
Hope it helps!

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What is the difference between the absolute value of 4 and the absolute value of negative 3?
Dmitry_Shevchenko [17]

Answer:

1

Step-by-step explanation:

Equation= |4| - |-3|=?

absolute value of 4 is 4. absolute value of -3 is 3.

So, 4-3=1, thus 1 is the answer

3 0
3 years ago
Read 2 more answers
What is the slope of the line graphed below? (PLEASE ANSWER IMMEDIATELY)
Dmitrij [34]

Answer:

-2/-3

Step-by-step explanation:

3 0
3 years ago
Jacob solves the system of equations by forming a matrix equation.
Lyrx [107]

Simultaneous equations can be solved using inverse matrix operation.

The complete steps of Jacob's solution are:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

We have:

4x + y = 2

-2x + 4y = -22

Calculate the determinant of \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

|A| = 4 \times 3 -1 \times -2

|A| = 12 +2

|A| = 14

So, the inverse matrix becomes

A = \frac{1}{14}\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

Replace the first column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of x

x = \frac{1}{14}\left[\begin{array}{cc}2&1\\-22&3\end{array}\right]

So, we have:

x = \frac{1}{14}(2 \times 3 - 1 \times -22)

x = \frac{1}{14}(6 +22)

x = \frac{1}{14}(28)

x = 2

Replace the second column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of y

y = \frac{1}{14}\left[\begin{array}{cc}4&2\\-2&-22\end{array}\right]

So, we have:

y = \frac{1}{14}(4 \times -22 - 2 \times -2)

y = \frac{1}{14}(-88 +4)

y = \frac{1}{14}(-84)

y = -6

Hence, the complete process is:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

Read more about matrices at:

brainly.com/question/11367104

6 0
3 years ago
Cos2A is equivalent to: A. sin2A−cos2A B. sin2A+cos2A C. cos2A−sin2A D. cosA−sinA
valina [46]

Formatted Options:

A. sin²A−cos²A

B. sin²A+cos²A

C. cos²A−sin²A

D. cosA−sinA

Answer:

C. cos²A−sin²A

Step-by-step explanation:

From the double angle formulas, we know that:

cos (A + B) = cosAcosB - sinAsinB

So, if B = A, then the above equation becomes;

cos(A + A) = cosAcosA - sinAsinA      [i.e replacing B with A]

=>cos(2A) = (cosA)² - (sinA)²

=> cos(2A) = cos²A - sin²A

Therefore,

cos(2A) is equivalent to cos²A - sin²A

6 0
3 years ago
A builder makes all of their ramps with a base to height ratio of 12:112:112, colon, 1 to be wheelchair-accessible. See the diag
Basile [38]

Answer:

The answer is 9.63

I got this answer from khan academy.

8 0
4 years ago
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