Has infinitely many solutions.
Answer:
The minimum number of assignment statements needed is 5
Step-by-step explanation:
To write the algorithm, we apply the strategy of interchanging the values of variables in the assignment statements.
Assume "tmp" is the new variable, let assign tmp to w
The algorithm is:
Procedure exchange (w,x,y,z: integers)
tmp := w
w := x
x := y
y := z
z := tmp
return (w,x,y,z)
end
From the algorithm, it is obvious that there will be a minimum of 5 assignment statements needed.
Step-by-step explanation:
false
0 can't he greater then any integer.
Answer:
x= - 1/c
Step-by-step explanation:
