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Answer: 
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Given: 
Find: 
Solution: In order to find the distance we need to use the distance formula, plug in the values, and simplify the expression.
<u>Plug in the values</u>
<u>Simplify the expression</u>
After simplifying the expression we were able to determine that the distance between the two points is 10.198 units.
Answer:
- x = arcsin(√20.5 -3√2) +2kπ . . . k any integer
- x = π - arcsin(√20.5 -3√2) +2kπ . . . k any integer
Step-by-step explanation:
Add √(82) -3sin(x) to both sides to get ...
2sin(x) = √82 -√72
Now, divide by 2 and find the arcsine:
sin(x) = (√82 -√72)/2
x = arcsin((√82 -√72)/2)
Of course, the supplement of this angle is also a solution, along with all the aliases of these angles.
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In degrees, the solutions are approximately 16.562° and 163.438° and integer multiples of 360° added to these.
5. 80, 16/.2=80
6. 679, 750-70.75
7. 7.82, 10-2.18
8. 36.07, 29.62+1.29+ 1.29+ 1.29+ 1.29+ 1.29