The answer is b hopefully I helped
Answer:
45 yards and 176 yards
Step-by-step explanation:
Perimeter of a rectangular playing field = 2(Length + width)
P = 2(L+W)..................... Equation 1
From the question,
Let the width of the rectangular playing field = x yards,
The the Length = 4x-4 yards.
Given: P = 442 yards.
Substitute these values into equation 1
442 = 2(4x-4+x)
442/2 = 5x-4
221 = 5x-4
5x = 221+4
5x = 225
x = 225/5
x = 45 yards.
Width = 45 yards.
Length = (45×4)-4 yards = 176 yards
Hence the dimensions of the playing field are, 45 yards and 176 yards
Answer:
A C(x) =2x³+2x²-18x-11
Step-by-step explanation:
C(x) = W(x) - D(x)
plug W(x) and D(x) into equation
C(x) = 3x³+4x²-18x+4 - (x³+2x²+15)
add like terms now
C(x) =2x³+2x²-18x-11
You can set this up as a system of equations.
x + y = 19
10x + 25y = 3.70
Your answer would be 31.42 dimes and -12.42 quarters.