Balanced chemical equation for ethanoic acid Please

02.04 Slide #2 Fill in the blanks based on the videos T Speed of reaction. When the of the reactants are moving too in a chemica

ale4655 [162]

Answer:

kylee is the best

Explanation:

5 0

3 years ago

How is carbon moved from the hydrosphere to the atmosphere?

inessss [21]

Answer:

Explained

Explanation:

the various ways of input of CO_2 into the atmosphere.

1.Dissolved CO 2 in the ocean is released back into the atmosphere by heating ocean surface water

2.Plant and animal respiration, an exothermic reaction involving the breakdown into CO 2 and water of organic molecules.

3. Degradation of fungi and bacteria which are responsible for breaking down carbon compounds in dead animals and plants(fossils) and convert carbon into CO2 when oxygen or methane is present.

4.Combustion of organic matter (that includes deforestation and combustion of fossil fuels) oxidizing to produce CO2;

5. Cement production when calcium carbonate (limestone) is heated to produce calcium oxide(lime), cement component, and CO2 are released;

4 0

3 years ago

The thermal decomposition of N2O5 obeys first-order kinetics. At 45°C, a plot of ln[N2O5] versus t gives a slope of −6.40 × 10−4

finlep [7]

Answer:

1,080 min

Explanation:

A first order reaction follows the law:

$rate=k[A]$ , where [A] is the concentraion of the reactant A.

Equivalently:

$\dfrac{d[A]}{dt}=-k[A]$

Integrating:

$\dfrac{d[A]}{[A]}=-kdt$

$\ln \dfrac{[A]}{[A_o]}=-kt$

Half-life means [A]/[A₀] = 1/2, t = t½:

t½ = ln (2) / k

That means that the half-life is constant.

The slope of the plot of ln [N₂O₅] is -k. Then k is equal to 6.40 × 10⁻⁴ min⁻¹.

Thus, you can calculate t½:

t½ = ln(2) / 6.40 × 10⁻⁴ min⁻¹

t½ = 1,083 min.

Rounding to 3 significant figures, that is 1,080 min.

5 0

3 years ago

calculate the number of oxygen atoms in a 90.0g sample of vanadium(v) oxide v2o5. be sure your answer has a unit symbol if neces

Alborosie

90.0 g of vanadium (V) oxygen sample has 1.50 x 10 24 oxygen atoms.

To determine the number of oxygen atoms in a vanadium oxide sample, the following steps must be made.

Step 1: Convert the mass of vanadium(V) oxide to mol of vanadium(V) oxide

mol vanadium(V) oxide = mass / molar mass

mol vanadium (V) oxide = 90.0 g / 181.88 g/mol

mol vanadium (V) oxide = 0.49483 mol

Step 2: Convert mol of vanadium (V) oxide to moles of oxygen using mole ratio

mol oxygen = mol vanadium (V) oxide * mole ratio O / mol V2O5

mol oxygen = 0.49483 mol * 5 mol O / mol V2O5

mol oxygen = 2.47416 mol O

Step 3: Convert to oxygen atoms using Avogadro's number

atoms oxygen = mol oxygen * 6.02214 x 10 23 atoms O /mol O

atoms oxygen = 2.47416 mol O * 6.02214 x 10 23 atoms O/mol O

atoms oxygen = 1.48997 x 10 24 atoms or 1.50 x 10 24 atoms O

To learn more about Avogadro's number, please refer to the link brainly.com/question/859564.

#SPJ4

4 0

2 years ago

HNO3 + H2O → H3O^+ + NO3 which ones are acids and which ones are bases

nlexa [21]

Answer:

HNO₃ and H₃O⁺ are acids

H₂O and NO₃⁻ are bases

Explanation:

The chemical equation is:

HNO₃ + H₂O → H₃O⁺ + NO₃⁻

There are several definitions of acid and bases: Arrhenius', Bronsted-Lowry's and Lewis'.

Bronsted-Lowry model defines and acid as a donor of protons, H⁺.

In the given equation HNO₃ is such substance: it releases an donates its hdyrogen to form the H₃O⁺ ion.

On the other hand, a base is a substance that accepts protons.

In the reaction shown, H₂O accepts the proton from HNO₃ to form H₃O⁺.

Thus, H₂O is a base.

In turn, on the reactant sides the substances can be classified as acids or bases.

H₃O⁺ contain an hydrogen that can be donated and form H₂O; thus, it is an acid (the conjugated acid), and NO₃⁻ can accept a proton to form HNO₃; thus it is a base (the conjugated base).

4 0

3 years ago

Balanced chemical equation for ethanoic acidPlease​

Balanced chemical equation for ethanoic acidPlease