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tamaranim1 [39]
4 years ago
6

Assume that the partial pressure of sulfur dioxide, pso2, is equal to the partial pressure of dihydrogen sulfide, ph2s, and ther

efore pso2=ph2s. if the vapor pressure of water is 28 torr , calculate the equilibrium partial pressure of so2 (pso2) in the system at 298 k.
Chemistry
1 answer:
Alex Ar [27]4 years ago
8 0
<span>Kp = PH2O^2/(PH2O)^2 To calculate SO2 is to have a Kp for the reaction let x=PSO2=PH2S Kp= (28/760atm)^2/x^3 x=cube root(0.03684)/Kp=PSO2</span>
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