The probability of an event is expressed as

Given:

The probability of drwing two blue balls one after the other is expressed as

For the first draw:

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).
Thus,

The probability of drawing two blue balls one after the other is evaluted as

The probablity that none of the balls drawn is blue is evaluted as

Hence, the probablity that none of the balls drawn is blue is evaluted as
(15x^3y^-8)÷(5x^2y^-4)
= 3xy^-4
(3x)/ y^4
Answer:
they are adjacent angles
Step-by-step explanation:
for adjacent angles

Answer:
Step-by-step explanation:
I've already answered this question.