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Elena-2011 [213]
3 years ago
5

When a hockey team gets possession of the puck, the following probabilities have been

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer: p(a given b) = p(a and b) / p(b)

a is the probability that they score.

b is the probability that they cross the blue line.

p(a and b) is given as .005

this is the probability that they cross the blue line and score.

p(b is given as .6

that's the probability that they cross the opposing blue line.

the formula becomes:

p(a given b) = .005 / .6 = .0083333333.....

that's what i get using the p(a given b) formula.

Step-by-step explanation:

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What is the result of adding these two equations?<br> 4x – 4y = -2<br> –9x – 4y = -3
kondaur [170]

Answer: -5x-8y=-5

Step-by-step explanation:

add right sides of equation and even them with result of adding right sides of equation

4x-4y-9x-4y=-2-3

-5x-8y=-5

5 0
3 years ago
wilson jarred 45 liters of jam after 5 days. how much jam did wilson jar if he spent 7 days making jam? solve using unit rates.
Natali5045456 [20]
45/5 = 9 jams a day
x/7 = 9
x= 63 jams a day

Hope this helps!
5 0
3 years ago
Identify the percent of change as an increase or a decrease. 50 pounds to 35 pounds
mojhsa [17]

Answer:

There is a 30% decrese.

Step-by-step explanation:

6 0
2 years ago
The marketing club at school is opening a student store. They randomly survey 50 students about how much money they spend on lun
Luden [163]

Answer:

The expected value for a student to spend on lunch each day = $5.18

Step-by-step explanation:

Given the data:

Number of students______$ spent

2 students______________$10

1 student________________$8

12 students______________$6

23 students______________$5

8 students_______________$4

4 students_______________$3

Sample size, n = 50.

Let's first find the value on each amount spent with the formula:

\frac{num. of students}{sample size} * dollar spent

Therefore,

For $10:

\frac{2}{50} * 10 = 0.4

For $8:

\frac{1}{50} * 8 = 0.16 l

For $6:

\frac{12}{50} * 6 = 1.44

For $5:

\frac{23}{50} * 5 = 2.3

For $4:

\frac{8}{50} * 4 = 0.64

For $3:

\frac{4}{50} * 3 = 0.24

To find the expected value a student spends on lunch each day, let's add all the values together.

Expected value =

$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24

= $5.18

Therefore, the expected value for a student to spend on lunch each day is $5.18

7 0
2 years ago
Find the solution of this system of equations.
Vilka [71]
The answer is (2,0)

Explanation

So I’m gonna use substitution to help me solve this problem. I’m gonna solve for x.

X-y=2

+y. +y

X= y + 2

Now that we have solved for x we are going to plug it into the first equation!
Shown like this


Y+2 - 10y = 2

Then we solve it as a normal problem

So first we combine light terms

-9y+2=2

Then we isolate the variable

-9y+2=2
-2. -2

-9y = 0

Then we divide by -9 on both sides

-9y /-9 = 0 / -9
Y = 0

Now that we solved for y we plug it into one the equations to get the x value!

X - 0 = 2
X=2

The solution is (2,0)

I hope this helped you! Pls mark as brainliest

6 0
3 years ago
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