Answer:
-25,-15,-5.5,0,15,25
Step-by-step explanation:
Answer:
76.16 kilograms of food
Step-by-step explanation:
Number of cyclist = 32
Food per cyclist = 8.33 kilograms
Days of the trip = 7 days
Food per cyclist per day = 8.33 kg / 7
= 1.19kg food per day for each cyclist
how many kilograms of food will the group be carrying at the end of Day 5?
5 days out of 7 days = 2 days
Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days
= 2 × 1.19
= 2.38 kilograms of food for two days
32 cyclist for 2 days = 32 × 2.38 kg of food
= 76.16 kilograms of food
The group will be carrying 76.16 kilograms of food at the end of Day 5
I think the answer is d. The slope of AC=Slope of DF.
Hope this helped☺☺
B.
<span>$5852.86
Working;
</span><span>A = P(1 + r)^t
A=5000(1+</span>
)^5
A=<span>5852.86</span>
