I think that the answer is A, because in the range, none of the numbers should be the same, and the numbers are all different in choice A
Replace x with y and solve for y~
y=2*
x=2^y
log x = y log 2
y=log x / log 2
Hope this helps and leave a brainliest to help me reach expert ;)
Answer:

Step-by-step explanation:
Hello!
The expression is written in the form of 
Let's factor by grouping:

The sum of the factors of -50 should add up to -23.
-25 and 2 work for this.
Expand and factor:
The factored expression is 
Answer:
David can run 28.7 miles in 3.5 hours.
Step-by-step explanation:
8.2mph × 3.5hours = 28.7miles
<em>good luck, i hope this helps :)</em>
Using it's concept, it is found that the mean absolute deviation of 2.8 means that the heights differ from the mean by an average of 2.8 inches.
<h3>What is the mean absolute deviation of a data-set?</h3>
- The mean of a data-set is given by the sum of all observations divided by the number of observations.
- The mean absolute deviation of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.
- The mean absolute deviation represents the average by which the values differ from the mean.
In this problem, the mean is given by:
M = (65 + 58 + 64 + 61 + 67)/5 = 63.
Hence the mean absolute deviation is given by:
MAD = (|65-63| + |58-63| + |64-63| + |61-63| + |67-63|)/5 = 14/5 = 2.8.
The mean absolute deviation of 2.8 means that the heights differ from the mean by an average of 2.8 inches.
More can be learned about mean absolute deviation at brainly.com/question/3250070
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