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Eduardwww [97]
3 years ago
10

PLS HELP!! with all problems

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0

Step-by-step explanation:

HSISGSJAH7EH7EIH yes✅✅ or not going on here I come back for a while ago but I'm not sure what I was so good for your loss and the other day and I was in the way it was a fan and I am not not to be on our relationship with me to do it again I was in my urgent need help me and I have to be a great time to be on my way to get a free total drama with a lot more then we will never be there in my heart is broken up to you and your phone number and I am so happy that is so beautiful I don't have time⌚ I don't think so much fun of

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Need help???! Explanation too please
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Answer:

When X=Y every number on either side is the same, for example 1(X)=1(Y)

Step-by-step explanation:

This is because when X=Y the X value isn't altered in any way to equal Y, so they are the same number, hope this helped!

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How do you write a percent into a fraction or a mixed number in simplest form
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3 years ago
Write the equation of the mirror line for the segment with endpoints (5, 4) and (-1, -1).
Kobotan [32]

The equation of the mirror line in standard form is: 10y+12x=39. The reflection of the point is A'(1,2)

Step-by-step explanation:

Given that the endpoints of the segments are: (5,4) and (-1,-1) then the equation of the mirror line will be;

slope=m=Δy/Δx

Δy= -1 - 4= -5

Δx= -1-5 = -6

m= -5/-6 = 5/6

For the equation, taking point (5,4), and (x,y), it will be;

m=Δy/Δx

5/6= y-4/x-5

5(x-5) = 6(y-4)

5x-25 =6y-24

5x=6y-24+25

5x=6y+1

5x-1=6y

6y=5x-1 -------divide both sides by 6

y=5/6x -1/6 -------Equation of line segment

The mirror line is a perpendicular bisector of the segment.This means it passes at the midpoint of the segment.

Finding the midpoint of the segment will be;

{(x₁+x₂)/2 ,(y₁+y₂)/2}

{(5+-1)/2, (4+-1)/2} =(4/2, 3/2) =(2, 3/2)

Using the coordinate point of the midpoint, you can find the equation of the mirror line knowing that the slope will be -6/5 because the mirror line is perpendicular to the line segment that has a slope of 5/6.

Finding the equation of the mirror line using point (2, 3/2), (x,y) and m= -6/5

\frac{y-1.5}{x-2} =\frac{-6}{5} \\\\5(y-1.5)=-6(x-2)\\5y-7.5=-6x+12\\5y-\frac{15}{2} =-6x+12\\\\10y-15=-12x+24\\\\10y+12x=15+24\\\\10y+12x=39

The equation of the mirror line in standard form is;

10y+12x=39

2. Given point A(3,-2)  and line y=1/2x -1 ,you can use a graph tool to plot the equation for the mirror line, plot the object point and locate the image point across the mirror line.

From the graph, the image is A'(1,2)

Learn More

Reflection of a point :brainly.com/question/12865568

Keywords : equation, mirror line, segment, endpoints, reflection

#LearnwithBrainly

5 0
3 years ago
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