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3 years ago

ASAP is the object of soccer ??????

1 answer:

n200080 [17]3 years ago

6 0

Soccer is a sport that has offense, people in the middle, and defense. The goal to playing soccer is to get past the defenders by using teamwork and score more goals than the other team to win.

You might be interested in

What is the wavelength of a wave that has a speed of 3 km/s and a frequency of 12 Hz

olasank [31]

Answer:

Wavelength = 250 m

Explanation:

[ Refer to the attached file ]

6 0

4 years ago

At which point is the potential energy the greatest? At which point is kinetic energy the greatest?

notsponge [240]

Answer:

Kinetic energy is greatest at the lowest point of a roller coaster and least at the highest point.

<h2>hope it helps you </h2><h2>make me as brainlylist </h2>

3 0

4 years ago

A seesaw made of a plank of mass 10.0 kg and length 3.00 m is balanced on a fulcrum 1.00 m from one end of the plank. A 20.0-kg

lidiya [134]

Answer:

7.5 kg

Explanation:

We are given that

$m_1=10 kg$

Length of plank, l=3 m

Distance of fulcrum from one end of the plank=1 m

$m_2=20 kg$

We have to find the mass must be on the other end if the plank remains balanced.

Let m be the mass must be on the other end if the plank remains balanced.

In balance condition

$20\times 1=10\times (1.5-1)+m\times (1.5+0.5)$

$20=10(0.5)+2m$

$20=5+2m$

$2m=20-5=15$

$\implies m=\frac{15}{2}$

$m=7.5 kg$

Hence, mass 7.5 kg must be on the other end if the plank remains balanced.

3 0

3 years ago

Read 2 more answers

The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top

vaieri [72.5K]

Answer:

v = 44,16 m/s

Explanation:

We will fixate our reference in the starting point from where Dan jumped of, at the top of the Casino. Therefore, the displacement made when dan reached the airbag would be of y= -99,4 m viewed from our reference. We describe the motion of dan with the equation:

$v_y^2 =v_0^2 +2ay$

Dan jumped from the rest, that means that the initial velocity v_0=0, therefore:

$v_y^2 =2ay \rightarrow v_y = \sqrt{2ay}$

Since Dan is moving in the negative axis regarding our reference point, we take the negative root of the equation.

v_y=-√(2*(-9,81 m/s^2 )*(-99,4 m) )=44,1613 m/s $v_y =- \sqrt{2*(-9,81 m/s^2)*(-99,4 m)} = 44,1613 m$

So, if we don’t take the air resistance into account, Dan would have achieved an velocity of 44,16 m/s when he reached the airbag.

I hope everything was clear with my explanation. If you need anything else, let me know. Have a great day :D

7 0

4 years ago

List six aspect of wellness discussed in class

julia-pushkina [17]

The correct answer for your question since you didn't post the choices i believe are Physical, Emotional, spiritual sometimes, intellectual, environmental, and lastly, social.

I hope this is correct and hope this rings a bell?

3 0

3 years ago