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Answer:
The option is B is not true for Hubble telescope.
The power equals energy divided by the time
P=E/t
P=1200/60
P=20W
Hope you get it!
For A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C, the amount of water that freezes onto the ice? is mathematically given as
x = 9.93 g
<h3>What is the amount of water that freezes onto the ice?</h3>
Where
Energy received = energy given out
Generally, the amount of water is mathematically given as
(53)(0.5)(30) = (80)(x)
Therefore
x = (49)(0.5)(16)/(80)
x = 9.93 g
In conclusion, the mass of water
x = 9.93 g
Read more about mass
brainly.com/question/15959704
Answer:
58.44 C
Explanation:
Electric field is found by
Therefore, the charge is


Therefore, required charge is 58.44 C