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ch4aika [34]
3 years ago
15

A seesaw made of a plank of mass 10.0 kg and length 3.00 m is balanced on a fulcrum 1.00 m from one end of the plank. A 20.0-kg

mass rests on the end of the plank nearest the fulcrum. What mass must be on the other end if the plank remains balanced?
Physics
2 answers:
allochka39001 [22]3 years ago
8 0

Answer:

The mass at the other end is 7.5 kg.

Explanation:

Let the mass is m.

Take the moments about the fulcrum.

20 x 1 = 10 x 0.5 + m x 2

20 = 5 + 2 m

2 m = 15

m = 7.5 kg

lidiya [134]3 years ago
3 0

Answer:

7.5 kg

Explanation:

We are given that

m_1=10 kg

Length of plank, l=3 m

Distance of fulcrum from one end of the plank=1 m

m_2=20 kg

We have to find the mass must be on the other end if the plank remains balanced.

Let m be the mass must be on the other end if the plank remains balanced.

In balance condition

20\times 1=10\times (1.5-1)+m\times (1.5+0.5)

20=10(0.5)+2m

20=5+2m

2m=20-5=15

\implies m=\frac{15}{2}

m=7.5 kg

Hence, mass 7.5 kg   must be on the other end if the plank remains balanced.

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