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labwork [276]
3 years ago
11

The diameter of an official squash ball ranges from 39.5 mm to 40.5 mm. What is the difference in volume between the larger and

smaller official squash ball?
Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

2513.41 mm³

Step-by-step explanation:

Given that,

The diameter of ball 1 = 39.5 mm

Radius of ball 1 = 19.75 mm

The volume of ball 1 is :

V_1=\dfrac{4}{3}\pi r^3\\\\=\dfrac{4}{3}\pi \times 19.75^3\\\\=32269.32\ mm^3

The diameter of ball 2, = 40.5 mm

Radius = 20.25 mm

Volume of ball 2,

V_2=\dfrac{4}{3}\pi \times 20.25^3\\\\=34782.73\ mm^3

Difference in volume = V₂ - V₁

= 34782.73 - 32269.32

= 2513.41 mm³

So, the difference in volume of the ball is equal to 2513.41 mm³.

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3 years ago
What is the corresponding growth decay factor of the given annual rate of +200%
Alina [70]
2000 should be it I'm pretty sure
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On a coordinate plane, a line goes through (negative 12, negative 2) and (0, negative 4). A point is at (0, 6).
mariarad [96]

Point (-12 , 8) is on the line that passes through (0, 6) and is parallel to the given line ⇒ 1st

Step-by-step explanation:

Parallel lines have:

  • Same slopes
  • Different y-intercepts

The formula of the slope of a line which passes through points (x_{1},y_{1}) and (x_{1},y_{1}) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ The given line passes through points (-12 , -2) and (0 , -4)

∴ x_{1} = -12 , x_{2} = 0

∴ y_{1} = -2 , y_{2} = -4

- Use the formula of the slope above to find the slope of the given line

∵ m=\frac{-4-(-2)}{0-(-12)}=\frac{-4+2}{12}=\frac{-2}{12}=\frac{-1}{6}

∴ The slope of the given line is \frac{-1}{6}

∵ The two lines are parallel

∴ Their slopes are equal

∴ The slope of the parallel line = \frac{-1}{6}

∵ The parallel line passes through point (0 , 6)

- The form of the linear equation is y = mx + b, where m is the slope

  and b is the y-intercept (y when x = 0)

∵ m = \frac{-1}{6} and b = 6

∴ The equation of the parallel line is y = \frac{-1}{6} x + 6

Let us check which point is on the line by substitute the x in the equation by the x-coordinate of each point to find y, if y is equal the y-coordinate of the point, then the point is on the line

Point (-12 , 8)

∵ x = -12 and y = 8

∵ y = \frac{-1}{6} (-12) + 6

∴ y = 2 + 6 = 8

- The value of y is equal the y-coordinate of the point

∴ Point (-12 , 8) is on the line

Point (-12 , 8) is on the line that passes through (0, 6) and is parallel to the given line

Learn more:

You can learn more about the equations of parallel lines in brainly.com/question/9527422

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
Find the shortest distance, d, from the point (5, 0, −6) to the plane x + y + z = 6.
DENIUS [597]

Answer:

\frac{7}{\sqrt{3}}

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |                   --------------------(i)

From the question,

the point is (5, 0, -6)

the plane is x + y + z = 6

Therefore,

a = 5

b = 0

c = -6

m = 1

n = 1

t = 1

r = 6

Substitute these values into equation (i) as follows;

d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |

d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |

d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

Therefore, the shortest distance from the point to the plane is  d = \frac{7}{\sqrt{3}}

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1. 5 + (-8) =
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Answer:

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Step-by-step explanation:

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