X – 0.25x = 0.75x

Mathematics

2 answers:

8090 [49]3 years ago

6 0

Answer: B

Step-by-step explanation:

Umnica [9.8K]3 years ago

3 0

Answer:

I think it will be D, because you will be decreasing 0.25x and increasing 0.75x, you will add 0.25x to -0.25x to get rid of 0.25x. Then you will need to do the same thing to the other side. You will add 0.25x to 0.75x so you will be increasing 0.75 since you will be adding to it.

Step-by-step explanation:

X – 0.25x = 0.75x

X-0.25x+0.25x=0.75x+0.25x

X= 1.00x

All you need to do is add 0.25x to both -0.25x and positive 0.75x. That way it will be equal.

So, I believe it will be D

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The following table shows the times of trains between Juno and Odiham.

Luba_88 [7]

Answer:

(a) The earliest time that Ferdo can be back at Juno station is 12:15

Step-by-step explanation:

From the given table, we have;

The starting time for train departure from Juno = 07:15

The frequency of train departures from Juno = Every 20 minutes

The time of departure, 't₁' of first train that departs from Juno after 08:30 is given as follows;

The train departure times from Juno = 07:15, 07:35, 07:55, 08:15, 08:35

Therefore;

The time at which the first train departs from Juno after 08:30 = 08:35

The time it takes a train to travel from Juno to Odiham = 0:805 - 07:15 = 50 minutes

The time of arrival of the train Ferdo takes from Juno at Odiham = 08:35 + 50 minutes = 09:25

The number of hours Ferdo spends at Odiham = 2 hours

The time after which Ferdo departs from Odiham = 09:25 + 02:00 = 11:25

The time of departure of the train from Odiham after 11:25 = 08:05 + 20 minutes × 10

Therefore, the time of departure of the train from Odiham after = 11:25

The time it takes on the trip back to Juno from Odiham = 50 minutes

The earliest time that Ferdo can be back at Juno station = 11:25 + 50 minutes = 12:15

8 0

3 years ago

Consider a multiple choice exam with 10 questions, and with 4 possible answers to each question (labeled A, B, C, and D). 1a. Wh

mrs_skeptik [129]

Answer:

(1a) 9.54e-07 (1b) 0.9437 (2) $10^8$

Step-by-step explanation:

We have n = 10 questions. For each question in the multiple choice exam, we can choose the correct answer with probability p = 0.25 or an incorrect answer with probability q = 0.75 (just by guessing). Besides is reasonable to believe that questions are independent. Let X be the random variable that represents the number of correct answers (just by guessing) observed during the n = 10 questions, so, X have a binomial distribution.

(a) The probability of getting a perfect score just by guessing is

$P(X = 10) = 10C10(0.25)^{10}(0.75)^{10-10} = 9.54e-07$

(b) The probability of getting at least one question correct, just by guessing

$P(X\geq1) = \sum_{x=1}^{x=10}10Cx(0.25)^{x}(0.75)^{(10-x)} = 0.9437$

2. Each RUID is 9-digits long, there are 10 digits, each of the nine positions for a digit of the RUID has 10 posibilities except the 4th and 5th positions which must be both 0. For the multiplication rule there can be $(10)^3(1)(1)(10)^5 = 10^8$ different RUIDS.