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3 years ago

PLSSS HELP!!!!!!!! What is the y-intercept of the function and what does it represent?

Mathematics

1 answer:

zlopas [31]3 years ago

6 0

Answer:

The y-intercept is $1000

Step-by-step explanation:

What this means is the the value of the antique when first found/created was 1000 dollars

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A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

3 years ago

12 is what percent of 96

DaniilM [7]

12 * 100 = 1200/96 = 12.5
Answer = 12.5%
You mulitply 12 by a hunndred, since a percent means "out of a hundred." Then, you divide that, by 96, since, you want to find the percent out of 96.

8 0

3 years ago

Help!<br> Change 2/5<br> to a percent.

nalin [4]

Answer:

40%

Step-by-step explanation:

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3 years ago

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Numbers with a sum of 1

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