The diagram shows three identical squares of side length 8 cm. The top square is exactly

Mathematics

1 answer:

Firlakuza [10]2 years ago

8 0

Bsbehgegdgrbshhsbzhsbdhzhzyegzzggsgsgsv

You might be interested in

The triangles below are similar because of the:

siniylev [52]

Answer:

AA similarity postulate

Explanation:

For triangle XZY, the angles are 90°, 40°, 50°.

For triangle AXB, the angles are 90°, 40°, 50°.

Which states that all the angles are of equal measure in the triangles.

This is stated by AA similarity theorem meaning when two angles are equal in the triangle. Then the triangles are congruent to each other.

7 0

2 years ago

(a) The function k is defined by k(x)=f(x)g(x). Find k′(0).

Brut [27]

Answer:

(a) k'(0) = f'(0)g(0) + f(0)g'(0)

(b) m'(5) = $\frac{f'(5)g(5) - f(5)g'(5)}{2g^{2}(5) }$

Step-by-step explanation:

(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use product rule,i.e., $\frac{\mathrm{d} [f(x)\times g(x)]}{\mathrm{d} x}=\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}$

this will give k'(x)=f'(x)g(x) + f(x)g'(x)

on substituting the value x=0, we will get the value of k'(0)

{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}

(b) m(x) is a function of two functions f(x) and g(x) [ $m(x)=\frac{1}{2}\times\frac{f(x)}{g(x)}$ ]. Since m(x) has a function g(x) in the denominator so we need to use division rule to differentiate m(x). Division rule is as follows : $\frac{\mathrm{d} \frac{f(x)}{g(x)}}{\mathrm{d} x}=\frac{\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}}{g^{2}(x)}$