When you are looking for this, the best way to do this is to divide 28 by 7. This will give you 4.
The other way to do this is to list the factors of 28, which are 1,2,4,7,14,28, and you will then be able to see which two are paired.
In this case, x is 4.
Hope I have been able to help you
Answer:
8, 9, 10
Step-by-step explanation:
three positive consecutive integers
x, x + 1, x + 2
the product of the smallest and the largest is 26 more than six times the middle integer
x(x + 2) = 6(x + 1) + 26
Expand
x^2 + 2x = 6x + 6 + 26
Combine like terms
x^2 + 2x = 6x + 32
Subtract 6x + 32 from both sides
x^2 - 4x - 32 = 0
Factor
(Alternately use the quadratic formula or complete the sqaure)
(x - 8)(x + 4)
x = {-4, 8}
-4 is extraneous because the integers must be positive
x = 8
x + 1 = 9
x + 2 = 10
8, 9, 10
Answer: 144
Step-by-step explanation: Its probally wrong
9514 1404 393
Answer:
![f^{-1}(x)=\dfrac{\sqrt[3]{x}+1}{2}}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7Bx%7D%2B1%7D%7B2%7D%7D)
Step-by-step explanation:
Interchange x and y in the function definition and solve for y.
![x=(2y-1)^3\\\\\sqrt[3]{x}=2y-1\qquad\text{take cube root}\\\\\sqrt[3]{x}+1=2y\qquad\text{add 1}\\\\y=\dfrac{\sqrt[3]{x}+1}{2}\qquad\text{divide by 2}\\\\\boxed{f^{-1}(x)=\dfrac{\sqrt[3]{x}+1}{2}}](https://tex.z-dn.net/?f=x%3D%282y-1%29%5E3%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%7D%3D2y-1%5Cqquad%5Ctext%7Btake%20cube%20root%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%7D%2B1%3D2y%5Cqquad%5Ctext%7Badd%201%7D%5C%5C%5C%5Cy%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7Bx%7D%2B1%7D%7B2%7D%5Cqquad%5Ctext%7Bdivide%20by%202%7D%5C%5C%5C%5C%5Cboxed%7Bf%5E%7B-1%7D%28x%29%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7Bx%7D%2B1%7D%7B2%7D%7D)