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2 years ago

Can anyone help me with this? Thank you

Mathematics

2 answers:

Sergeeva-Olga [200]2 years ago

8 0

1. 3,6

2. 5,6

3. 4,5

(branliest will be appreciated and thanks)

Veseljchak [2.6K]2 years ago

3 0

Slope: 3/5
Y intercept: -3
X-intercept: 5

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sample daat reflects shipments received from 3 different vendors Vendor Defective Acceptable 1 16 133 2 25 74 3 24 187 what is c

Sergeu [11.5K]

Question: W<span>hat is the correct hypothesis to determine if quality is associated with vendor?

By looking at other resources, I have found the choices given for this question. They are the following:

a. Null</span>: Quality and source of shipment (vendor) are independent; Alternative: Quality and source of shipment (vendor) are dependent.
b. Null: Quality and source of shipment (vendor) are dependent; Alternative: Quality and source of shipment (vendor) are independent.

The test that would be applicable for this type of data would be the Chi-Square Test for Independence. As the name implies, the null hypothesis should be that the two factors are independent since that will be what we will be testing for.

ANSWER: a. Null: Quality and source of shipment (vendor) are independent; Alternative: Quality and source of shipment (vendor) are dependent.

Question: Calculate the value of the test statistic.

Please refer to the attached document for the complete computation for this part. Generally, we need to find the expected value for each cell in the table and perform some calculation explained in the document.

ANSWER: The test statistic is 12.80.

Question: S<span>pecify decision rule at the 1% significance level.

We can get the critical value for Chi-square tests by first looking for the degree of freedom. We can get the df by evaluating the following expression: (rows-1)*(columns-1). In our case, the number of columns is 2 and the number of rows is 3. The df is therefore (2-1)(3-1)=(1)(2)=2.

We then look at a table to determine what the value at the 1% significance level and df of 2 is.

ANSWER: We reject the null hypothesis if the test statistic is greater than the critical value which is 9.2103.

Question: What is your conclusion?
</span>
Since the test statistic (12.80) is greater than the critical value (9.2103), we can therefore tell that it is in the area for rejection.

Thus, we reject the null hypothesis.

ANSWER: There is enough evidence to conclude that the quality and source of shipment (vendor) are NOT independent.

Download docx

5 0

3 years ago

Please help me, what is the answer?

frutty [35]

Yes, pentagon prism

8 0

2 years ago

The square below represents one whole.

kupik [55]

Answer:

$\text{Shaded area as fraction}=\frac{81}{100}$

$\text{Shaded area as decimal}=0.81$

$\text{Shaded area as percent of the whole}=81\%$

Step-by-step explanation:

Please consider the attached image as the given square.

We are asked to express the shaded area as a fraction, a decimal, and a percent of the whole.

We can see that in our figure there are 100 squares as there are 10 rows and each row contains 10 squares.

We can also see that there are 81 shaded squares out of 100 squares, so we can represent it as a fraction as:

$\frac{\text{Shaded squares}}{\text{Total squares}}$

$\text{Shaded area as fraction}=\frac{81}{100}$

To convert the shaded area into decimal, we need to divide 81 by 100.

$\text{Shaded area as decimal}=0.81$

To convert the shaded area into percent, we need to multiply 0.81 by 100.

$\text{Shaded area as percent of the whole}=0.81\times 100\%$

$\text{Shaded area as percent of the whole}=81\%$

7 0

3 years ago

Read 2 more answers

Please help me now plz <br> I will mark you brainliest

cluponka [151]

Answer:

not clear enough to answer your question

3 0

3 years ago

The football team has a total of 350 jerseys. There are 154 medium-sized jerseys. What percent of the jerseys are medium-sized

KonstantinChe [14]

Answer:

Step-by-step explanation:

Given : The total number of jerseys = 350

The number of medium-sized jerseys = 154

Then, the percent of the jerseys are medium-sized jerseys will be :-

\begin{gathered}\dfrac{\text{Number of medium-sized jerseys }}{\text{Total jerseys}}\times100\\\\=\dfrac{154}{350}\times100\\\\=0.44\times100=44\%\end{gathered}

Total jerseys

Number of medium-sized jerseys

×100

350

154

×100

=0.44×100=44%

<h3>Therefore , the percent of the jerseys are medium-sized jerseys = 44%</h3>

6 0

2 years ago

Read 2 more answers