hi
monthly interest rate is :
So in forty month there will be : 10 000 * ( )^40 ≈11 776,06
Can anyone help me with this? Thank you
2 answers:
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Answer:
2196 fish
Step-by-step explanation:
Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb
Weight of the fish that killer whale might eat in a day = lb.
Average weight of the fish that killer whale eats = 3.4 oz
Since,
1 pound(lb) = 16 ounces(oz)
So,
Weight of the fish that killer whale might eat in a day in ounces(oz) = oz
Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.
So, the number of fish that killer whale would eat = fish
Thus, the killer whale needs to eat 2196 fish.
Answer:
A)29 and B) 21,
Step-by-step explanation:
First,in the sequence , the parameter
must to be a integer.
Second, we need to solve the equations by .
All the option in the problem represent an
Then, we need to prove all number in the options, if the result is a integer number, this option can be part of the sequence.
For A)
For B)
For C)
For D)
Only A) and B) only A and B meet the requirement