Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get
Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
Answer:
x ≈ 42.5
Step-by-step explanation:
We use tan∅ to solve this:
tanx° = 11/12
x° =
x = 42.5104°
It depend on what question an algebric can have as many but depends???
Answer:
5/6
Step-by-step explanation:
- 2/3 ÷ 4/5 = ⇒ <em>changing division to multiplication by reciprocal of the second fraction</em>
- 2/3 × 5/4 = ⇒ <em>simplify and multiply numerators and denominators</em>
- 5/6 ⇒ <em>here is the answer</em>
Answer:
36:85
Step-by-step explanation:
Given the right angled triangle as shown in the attachment, the cos of angle N can be gotten by simply using the CAH method in SOH CAH TOA.
According to CAH
Cos∠N = Adjacent/Hypotenuse
Hypotenuse is the longest of the triangle |ON| = 85
Since the opposite side to ∠N is 77, the third side will be the Adjacent side.
Adjacent side will be |NP| = 36
Therefore:
Cos∠N = 36/85
The ratio that represents the cosine of ∠N is 36:85