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3 years ago

Identify the Terms, Constants, Coefficients and Variables in the following eqaution:

Mathematics

1 answer:

irinina [24]3 years ago

5 0

Answer:

<h2>13x - 1. Term</h2><h2>5y - 1. Term</h2><h2>13 - 3. Coefficient</h2><h2>2 - 2. Constant</h2><h2>5 - 3. Coefficient</h2><h2>y - 4. Variable</h2><h2>3 - 2. Constant</h2><h2>x - 4. Variable</h2>

Step-by-step explanation:

<h3>13x + 5y - 2 = 3</h3><h3 /><h3><u>Term</u> has a <em>number and also a variable</em>. </h3><h3>Ex.: 5y</h3><h3 /><h3><u>Constant</u> is any <em>number without a variable</em>.</h3><h3>Ex.: 3</h3><h3 /><h3><u>Coefficient</u> is the <em>number in a term</em>.</h3><h3>Ex.: 13</h3><h3 /><h3><u>Variable</u> is any <em>letter</em> in the equation.</h3><h3>Ex.: x</h3><h3 />

$\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}$

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Find the coordinates of the midpoint of the segment with the given endpoints.

lesantik [10]

Answer:

The midpoint is (4,3)

Step-by-step explanation:

I attached the midpoint formula.

2 2

8 / 2 = 4 6 / 2 = 3

(4,3)

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2 years ago

Find the value of x..helppp

alekssr [168]

Answer:

For the diagram to be a parallelogram, then the measure of x is 4

Step-by-step explanation:

If the diagram is a parallelogram, then the diagonals bisect each other

What this mean is that they divide each other into 2

Mathematically, this means that the values AC is divided into two equal parts AE and CE

That means;

5x + 28 = 3x + 36

5x-3x = 36-28

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x = 8/2

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2 years ago

What is the <br> the sum of the multiples of 35 rom 36 to 153

Scorpion4ik [409]

Answer:

70, 105, 140

Step-by-step explanation:

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2 years ago

Find the mass of the triangular region with vertices (0, 0), (3, 0), and (0, 1), with density function ρ(x,y)=x2+y2.

ololo11 [35]

Since density is the ratio of mass to (in this case) area, we can find the mass of the triangular region $\mathcal T$ by computing the double integral of the density function over $\mathcal T$ :

$\mathrm{mass}=\displaystyle\iint_{\mathcal T}\rho(x,y)\,\mathrm dx\,\mathrm dy$

The boundary of $\mathcal T$ is determined by a set of lines in the $x,y$ plane. One way to describe the region $\mathcal T$ is by the set of points,

$\mathcal T=\left\{(x,y)\mid0\le x\le 3\,\land\,0\le y\le1-\dfrac x3\right\}$

So the mass is

$\mathrm{mass}=\displaystyle\int_{x=0}^{x=3}\int_{y=0}^{y=1-x/3}(x^2+y^2)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2y+\frac{y^3}3\right)\bigg|_{y=0}^{y=1-x/3}\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2\left(1-\frac x3\right)+\frac{\left(1-\frac x3\right)^3}3\right)\,\mathrm dx$

$=\displaystyle\frac1{81}\int_0^3(27-27x+90x^2-28x^3)\,\mathrm dx=\frac52$

6 0

3 years ago

65 people took a clarinet exam. Before the exam, 23 people predicted that they would pass, and the rest predicted they would fai

kakasveta [241]

Answer:

The answer is 29/42

Step-by-step explanation:

First, let's calculate how many people predicted they would fail. The question states that 65 people took the exam and 23 predicted they would pass, so we can find the number of people that predicted they would fail by the following calculation:

Let FP be the people who predicted they'd fail

65 = 23 + FP

65 - 23 = FP

42 = FP

Now, let's move on to the next part. The question states that a total of 31 people passed the test, from those 18 being the people who predicted they would pass and the rest are people who had predicted they would fail but ended up passing.

Let's set x as the number of people who predicted they would fail but have passed.

31 = 18 + x

31 - 18 = x

13 = x

Since 13 of the 42 FP have passed, we can calculate how many of them failed. Let y be the number of people that predicted to fail and ended up failing:

13 + y = 42

y = 42 - 13

y = 29

Finally, now we have the fraction of those who predicted that they would fail actually did fail and that's 29/42

3 0

1 year ago