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suter [353]
3 years ago
14

20% of Aussies have blue

Mathematics
1 answer:
notsponge [240]3 years ago
6 0

Answer:

20

Step-by-step explanation:

Step 1: 4 = 20% × Y

Step 2: 4 = 20/100 × Y

Multiplying both sides by 100 and dividing both sides of the equation by 20 we will arrive at:

Step 3: Y = 4 × 100/20

Step 4:Y = 4 × 100 ÷ 20

Step 5: Y = 20

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Let A= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Suppose an element of A is randomly selected. What is the probability that it belongs to
gregori [183]
<h3>Answer:  3/5</h3>

============================================================

Explanation:

The set {1, 2}U{2, 6, 7, 9}U{5, 6, 7} simplifies to {1,2,5,6,7,9} after we combine everything and sort the values. We toss any duplicates.

Let B = {1,2,5,6,7,9}

There are 6 items in set B out of 10 items in set A.

The probability of landing in set B, if you pick something randomly from A, is 6/10 = 3/5

8 0
3 years ago
Read 2 more answers
What is 4x-7xy+9xy-7pq
konstantin123 [22]
Answer:  " 4x + 2xy - 7pq " .
___________________________________
Explanation:
___________________________________
Given:  
" <span>4x - 7xy + 9xy - 7pq " ;  Simplify the expression;
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  Combine the "like terms:
___________________________________
       -7xy + 9xy = 2xy ;
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Now, rerewrite the expression, substituting the "-7xy + 9xy";  with " + 2xy" ;
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   </span>→ " 4x + 2xy - 7pq " .
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</span>
4 0
3 years ago
A teacher wants to test the effectiveness of two
GaryK [48]

Answer: an experiment

3 0
3 years ago
X^2 -9X = 0. Factor and use the Zero property to solve
Veseljchak [2.6K]
The first step of factoring is to try to factor out a common factor.
The terms x^2 and -9x have the factor x in common.
Factor out x from both terms.

x^2 - 9x = 0

x(x - 9) = 0

Now you have a product of fully factored terms equaling zero, so you can apply the zero product property to solve.

x = 0   or   x - 9 = 0

x = 0   or   x = 9

Answer: x = 0 or x = 9
5 0
3 years ago
100 point to the first correct answer
miss Akunina [59]

Answer:

X ~ B(n, p)

Given: X ~ B(2, 5/17)

⇒  n = 2

⇒  p = 5/17

Binomial distribution formula:

\sf P(X = x) = nC_x (1-p)^{(n-x)}p^x

As n = 2, calculate P(X = 0), P(X = 1) and P(X = 2):

\sf P(X = 0) = 2C0 (\frac{12}{17})^{(2-0)}(\frac{5}{17})^0=\dfrac{144}{289}}

\sf P(X = 1) = 2C1 (\frac{12}{17})^{(2-1)}(\frac{5}{17})^1=\dfrac{120}{289}}

\sf P(X = 2) = 2C2 (\frac{12}{17})^{(2-2)}(\frac{5}{17})^2=\dfrac{25}{289}}

**Probability Distribution Table attached**

5 0
2 years ago
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