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3 years ago

3.1 divide by 98.58 equals

Mathematics

2 answers:

Semmy [17]3 years ago

5 0

Answer:

5/159

Step-by-step explanation:

3 1/10 ÷ 98 58/100

convert into mixed number:

31/10 ÷ 9,858/100

flip the fraction and multiply:

31/10 • 100/9,858

simplify:

10/318 = 5/159

Makovka662 [10]3 years ago

3 0

Answer:

0.03144654088

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How much is 1 foot line of quarters worth

Alborosie

a quarter is 1.75 mm thick

1 mm = 0.0393701 inches

0.0393701/12 = 25.4 mm per inch

25.4/1.75 = 14.5 quarters per inch

14.5 x 12 = 174 quarters per foot

174 x 0.25 = 43.50

$43.50 for a foot of quarters

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4 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

Find the distance AB

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

Find the distance BC

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

Find the distance AC

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

Find the distance DC

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

Find the perimeter of the triangle

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

Find the area of the triangle

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

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3 years ago

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lesya [120]

The answer is 9.5% by simply diving 2000/210

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3 years ago

How to solve this problem? -3 d +7 > 25

sp2606 [1]

Answer to your question:

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3 years ago

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Do alto de um farol cuja altura é de 20 m avista se um navio sob ângulo de depressão de 30°. A que distância , aproximadamente,

Mkey [24]

Esta é a trigonometria . Se você desenhar uma linha a partir do topo da casa de luz para o barco, você terá a hypotonuse de um triângulo. Um truque é lembrar que este é um triângulo especial. É um triângulo 30-60-90 , que tem propriedades especiais mostradas na fixação abaixo . por isso sabemos que o lado adjacente que não é o hyposonuse é x√3 . Agora sabemos que x√3 = 20
Solve for x.
x√3=20
divide both sides by √3.
x=20/(√3)
Try not to have square roots (√) in denomenator so multiply top and bottom by √3 and get
x=(20√3)/3
x is what we are looking for so the answer is 
20√3 m ou cerca de 34.64 m

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4 years ago