Can someone solve these? I’ll give Brainliest !! Solve for x

1) Kyla paid a rental company a one-time fee of $100 plus $25 per day to rent a car. For

IrinaVladis [17]

Answer:

14 days

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

25n+100=450

Step 2: Subtract 100 from both sides.

25n+100−100=450−100

25n=350

Step 3: Divide both sides by 25.

25n/25 =350/25

n=14

5 0

3 years ago

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Someone please help me!!!!

BARSIC [14]

Answer: see proof below

Step-by-step explanation:

Use the Double Angle Identity: cos 2A = 2cos²A - 1

Use the Difference Identity: cos (A - B) = cosA · cosB + sinA · sinB

Use the Unit Circle to evaluate: cos (π/2) = 0 & sin (π/2) = 1

Proof LHS → RHS

$\text{Given:}\qquad \qquad \qquad \qquad 2\cos^2\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)-1\\\\\\\text{Double Angle Identity:}\quad \cos2\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)\\\\\\\text{Simplify:}\qquad \qquad \qquad \quad \cos\bigg(\dfrac{\pi}{2}-A\bigg)\\\\\\\text{Difference Identity:}\qquad \cos\dfrac{\pi}{2}\cdot \cos A+\sin \dfrac{\pi}{2}\cdot \sin A\\\\\\\text{Unit Circle:}\qquad \qquad \qquad 0\cdot \cos A+1\cdot \sin A\\\\\\\text{Simplify:}\qquad \qquad \qquad \qquad \sin A$

LHS = RHS: sin A = sin A $\checkmark$

4 0

4 years ago

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Bastien, Inc. has been manufacturing small automobiles that have averaged 50 miles per gallon of gasoline in highway driving. Th

alexira [117]

Answer:

We conclude that the the manufacturer's advertising campaign is not correct.

P-value of test = 0.067.

Step-by-step explanation:

We are given that an independent testing service road-tested 36 of the automobiles. The sample showed an average of 51.5 miles per gallon. The population standard deviation is 6 miles per gallon.

We have to conduct a test to determine whether or not the manufacturer's advertising campaign is legitimate.

Let $\mu$ = population average gasoline of new small cars in highway driving.

SO, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 50 miles per gallon {means that the manufacturer's advertising campaign is not correct}

Alternate Hypothesis, $H_A$ : $\mu$ > 50 miles per gallon {means that the manufacturer's advertising campaign is correct}

The test statistics that will be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average gasoline = 51.5 miles per gallon

$\sigma$ = population standard deviation = 6 miles per gallon

n = sample of automobiles = 36

So, test statistics = $\frac{51.5-50}{\frac{6}{\sqrt{36} } }$

= 1.50

Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is less than the critical values of z as 1.50 < 1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Also, P-value is given by the following formula;

P-value = P(Z > 1.50) = 1 - P(Z $\leq$ 1.50)

= 1 - 0.93319 = 0.067 or 6.7%

Therefore, we conclude that the the manufacturer's advertising campaign is not correct as its new small cars average less than or equal to 50 miles per gallon in highway driving.

3 0

4 years ago

A typist can type 1800 words in 1 hour.Find the number of words that he can type per minute

Georgia [21]

Answer:

1800 words = 1 hour

1800 words = 60 minutes

Divide by 60: 30 words per minute.

Let me know if this helps!

6 0

3 years ago

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350/100 as a decimal and a percent

IceJOKER [234]

Hey there

350/100 as a decimal.
To make fraction into decimal you divide the numerator by the denominator.

350/100
350÷ 100 =3.5

350/100 as a decimal is 3.5

TO convert to percent you have to multiply decimal by 100.

3.5 x 100 = 350
350 is the percent
350%

8 0

4 years ago

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