BRAINLIESTTT ASAP! PLEASE HELP ME :) Find the measure of ∠WZX. Show your work.

Mathematics

2 answers:

Soloha48 [4]3 years ago

7 0

The exterior opposite angle is the same as the sum of the alternate interior angles.

We can write an expression and solve for x.

(18x + 5) = 48 + (8x - 3)

~Remove parenthesis

18x + 5 = 48 + 8x - 3

~Combine like terms

18x + 5 = 45 + 8x

~Subtract 5 to both sides

18x + 5 - 5 = 45 + 8x - 5

~Simplify

18x = 40 + 8x

~Subtract 8x to both sides

18x - 8x = 40 + 8x - 8x

~Simplify

10x = 40

~Divide 10 to both sides

10x/10 = 40/10

~Simplify

x = 4

Now, substitute to find ∠WZX

18x + 5

18(4) + 5

72 + 5

Therefore, the answer is 77°

Best of Luck!

givi [52]3 years ago

4 0

Answer:

Step-by-step explanation:

48+8x-3=18x+5

45-5=18x-8x

40=10x

x=4

18*4+5=77

You might be interested in

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$