Answer:
The first step in solving 83.5 ÷ 6.25 is to multiply the divisor and dividend by
[✔ 100
]
sorry idk the answer for the second one :(
Step-by-step explanation:
This question is basically asking you what number was this originally until we timesed it by 100. For the first column take away two zeros or for answers like 560 and 4830 imagine there is a decimal point at the end and move it two spaces forward so it would now be 5.6 and 48.3
For the second column add two zeros at the end instead.
For the questions at the bottom basically for all the questions except the bottom one how many numbers follow the first number.
For example.
96,629 = 1
100
Because three numbers follow the first 6.
Hope this makes sense because I don’t know if it does.
Answer:
h(x) ≥ |x - 5| +1
Step-by-step explanation:
Given graph represents an absolute function (parent function)
f(x) = |x|
Since, graph of the function 'f' has been shifted 5 units to the right new function will be,
g(x) = f(x - 5)
g(x) = |x - 5|
Again function 'g' is shifted 1 unit upwards along the y-axis then the new function will be,
h(x) = g(x) + 1
h(x) = |x - 5| + 1
There is a shaded region representing the solution area lying above the intersecting dark lines,
Therefore, solution region will be re[presented by the inequality,
h(x) ≥ |x - 5| + 1
Answer:
x = 7
Step-by-step explanation:
Similar figures have sides that are proportional. Setting up a proportion for the sides of the figures will help solve for 'x':
Cross-multiply: 3(x + 1) = 6(x - 3)
Distribute: 3x + 3 = 6x - 18
Combine like terms: 21 = 3x
Solve for 'x': x = 7
<h3>
Answer: D) 5</h3>
Reason: It's the largest exponent
When a polynomial is written in standard form like this, the term with the largest exponent is written first, then the next largest and so on. So in cases like this, we simply need to look at the left-most term; however, this may not always be the case as your teacher could easily mix up the terms to make sure you're paying attention.
This is considered a quintic polynomial due to the degree of 5.