Answer:
question5: F=74312.5N
question6: charge at the end of antenna=0.37N
Explanation:
Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.
⇒
∴
where 
is the force of attraction or repulsion
is Coulumb's constant=
and 
are the magnitude of the charges
is the distance between two charges
The force between the two charges is attractive if they are of different polarity
The force between the two charges is repulsive if they are of same polarity
Question5:
Given: q1=0.041 C, q2=0.029 C, r=12 m
therefore by Coulumb's law,
Question6:
Given: q1=
, r=5 m, F=
therefore by Coulumb's law,
⇒
The term that best describes how many waves that pass? It's frequency because how many waves are passed by a given point or time is called the waves frequency. I hope this helped you out on your assignment.
The mass is 222g. No, it is less than 1kg. There are 1000 grams in a kilogram so it would be 0.222kg. Hope this Helps :D
Answer:
Explanation:
Expression for relative velocity
= 
= (.54 + .82 )c/ 
= 1.36 c / 1.4428
= .94 c
β = .94
Taking specific heat of lead as 0.128 J/gK = c
We have energy of ball at 7.00 meter height = mgh = 
When leads gets heated by a temperature ΔT energy needed = mcΔT
= 
ΔT
Comparing both the equations
= ΔT
ΔT = 0.536 K
Change in temperature same in degree and kelvin scale
So ΔT = 0.536 
