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Answer:
range is between 55.5 to 64.5
Step-by-step explanation:
Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches
68% is 1 standard deviation from mean
To get the range of 1 standard deviation we add and subtract standard deviation from mean
mean = 60
standard deviation = 4.5
60 - 4.5= 55.5
60+4.5 = 64.5
1 standard deviation is between 55.5 to 64.5
That is 68% range is between 55.5 to 64.5
H=height
y=number of years.
we have the next expresion:
h(y)=my+b
m=the slope of the line, in this case, the slope is equal to "18"; (18 cm/ year).
b=the initial heigth, in this case, the initial heigth is equal to "5" (5 cm).
Therefore, our expression will be:
h(y)=18y +5
answer: h(y)=18y+5