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3 years ago

A tutor works with a group of students. She charges $40 for the tutoring session plus $30 for each student in the group.

1 answer:

4 0

If it’s just 40 in total for the whole session , $40 + (30 x (number of students) = ?
But if it’s 40 per student as well then (40 x 30) x (number of students) = ?

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1) (-7.-3).(-5, -8)<br> What’s the distance between each pair?

anyanavicka [17]

Answer:

-2.5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Pls help if I don’t finish today mom will hurt me

kherson [118]

Answer:

We conclude that:

g(10) = 8

Step-by-step explanation:

First, we need to clear some concepts on how to fetch input and output from the function graph.

Determining the y-intercept:

We know that the y-intercept of the graph function can be determined by setting x = 0 and determining the corresponding y-value.

From the graph it is clear that x = 0, the value of y = 5. In other words, the graph intersects the y-axis at y = 5.

Therefore, the y-intercept of the graph is (0, 5).

Thus,

g(0) = 5

Determining the x-intercept:

We know that the x-intercept of the graph function can be determined by setting y = 0 and determining the corresponding x-value.

From the graph, it is clear that y = 0, the value of x = -10. In other words, the graph intersects the x-axis at x = -10.

Therefore, the x-intercept of the graph is (-10, 0).

Thus,

g(-10) = 0

Determining g(10):

From the graph, it is clearly visible that at x = 10, the value of the function output y = 8.

In other words,

at x = 10, g(10) = 8

Therefore, we conclude that:

g(10) = 8

5 0

3 years ago

Find the area of the right triangle. If necessary, round to the nearest tenth

Ad libitum [116K]

Answer:

B. 150 yards

Step-by-step explanation:

Area of a Triangle = .5 * Base * height

So we need the height of the triangle, or the missing side.

We have to use Pythagorean Theorem to solve this:

A^2 + B^2 = C^2

15 ^ 2 + B ^ 2 = 25 ^2

b^2 = 25^2 - 15 ^ 2

b^2 = 625 - 225

b^2 = 400

sqrt (400) = 20

The missing height is 20. Now we plug it into 1/2 * b * H

.5 * 15 * 20

7.5 * 20 = 150

150 Yds

6 0

3 years ago

What is the primary difference between exponential and linear functions?

Yanka [14]

Answer:

Step-by-step explanation:

We know that the growth of a linear function will always be constant. So, that eliminates B and C.

A quadratic function can be a function such as $x^2$ , or $5x^2+7x$ , etc.

An exponential function wouldn't be $x^2$ , it would be $2^x$ ! Or $3^x$ , or $(1.738283)^x$ , etc. Therefore, D is eliminated.

So, the answer is $\boxed{A}$ and we're done!

4 0

2 years ago

Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than

Fittoniya [83]

Inequation 1:

$\frac{2}{3}x-3 \geq y$

to plot the pairs (x, y) for which the inequation holds, draw the line $y=\frac{2}{3}x-3$

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2:

$y+ \frac{2}{3}x\ \textless \ 4$

$y\ \textless \ - \frac{2}{3} x+ 4
$

draw the lines

i) $y=\frac{2}{3}x-3$ use points (0, -3), (3, -1)

ii) $y=- \frac{2}{3} x+ 4$ use points ( 0, 4), (3, 2)

let's use the point P(3, 3) to see what region of the lines need to be coloured:

$\frac{2}{3}x-3 \geq y$ ;
$\frac{2}{3}(3)-3 \geq 3$
$2-3 \geq 3$ , not true so we color the region not containing this point

$y+ \frac{2}{3}x\ \textless \ 4$
$(3)+ \frac{2}{3}(3)\ \textless \ 4$
$3+ 5\ \textless \ 4$ not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.

4 0

3 years ago