Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: the amount a 10-11-year-old spends on a trip to the mall.
Assuming that the variable has a normal distribution, you have to construct a 98% CI for the average of the amount spent by the 10-11 year-olds on one trip to the mall.
For this you have to use a Student-t for one sample:
X[bar] ± *
n= 6
$18.31, $25.09, $26.96, $26.54, $21.84, $21.46
∑X= 140.20
∑X²= 3333.49
X[bar]= ∑X/n= 140.20/6= 23.37
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/5[3333.49-(140.2)²/6]= 11.50
S= 3.39
X[bar] ± *
[23.37 ± 3.365 * ]
[18.66;29.98]
With a confidence level of 98%, you'd expect that the interval $[18.66;29.98] will include the population mean of the money spent by 10-11 year-olds in one trip to the mall.
I hope you have a SUPER day!
answer : the answer is - 1 using Y2 - y1 over X2 minus X1
Answer:
Yes, this is a proportional relationship.
Step-by-step explanation:
It's a steady increase for both the x axis and y axis. The x axis increases by 1, and the y axis increases by 1 1/2. It doesn't veer from those increases.
I hope this helps!
First change the mL to liters:
Orange Juice: 1L
Lemon juice: 550mL=0.55L
Soda Water: 2.6L
Apple cider: 2*750=1500mL=1.5L
Then add them all together:
1+0.55+2.6+1.5=5.65
Lastly, multiply that number by 5:
5.65*5=28.25
Tammy will make 28.25 Liters of punch.
Answer:
54 R 6
Step-by-step explanation:
960 / 18 = 53 with a remainder of 6