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1 year ago

The radius of a circle is 10 miles. What is the length of a 45° arc?

Mathematics

1 answer:

pshichka [43]1 year ago

6 0

Solution

We are given

Radius (r) = 10 miles

Angle (theta) = 45 degrees

We want to find the length of the arc

Note: Formula for the length of an Arc

$\begin{gathered} l=\frac{\theta}{360}\times2\pi r \\ length\text{ }Of\text{ }Arc=\frac{45}{360}\times2\times\pi\times10 \\ length\text{ }Of\text{ }Arc=\frac{1}{8}\times20\pi \\ length\text{ }Of\text{ }Arc=\frac{5}{2}\pi \\ length\text{ }Of\text{ }Arc=7.853981634 \\ length\text{ }Of\text{ }Arc=7.854miles \end{gathered}$

Therefore, the length of the arc is

$\begin{equation*} 7.854miles \end{equation*}$

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Find the equation of the line passing through the points (3,-2) and (4,6) in slope intercept form.

noname [10]

Hey!

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They already give us the slope, so we can solve the y-intercept.

We can use (3, -2).

y = 8x + b

-2 = 8(3) + b

-2 = 24 + b

-2 - 24 = 24 + b - 24

-26 = b

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Hence, the answer is $\Large\boxed{\mathsf{y~=~8x~+~-26}}$

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Hope This Helped! Good Luck!

4 0

3 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

4 years ago

A set of scores with a normal distribution has a mean of 50 and a

dimaraw [331]

36, 43, 50, 57, 64

36 and 64 are two standard deviations out, so the empirical rule tells us 95% of scores will fall here with a normal distribution

4 0

3 years ago

There is a bag filled with 3 blue and 4 red marbles. A marble is taken at random from the bag, the colour is noted and then it i

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

8 0

3 years ago

What are two decimals equivalent to 3.51?

Margaret [11]

The answer is 3.5100 and 3.510.

5 0

3 years ago

Read 2 more answers