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jasenka [17]
3 years ago
6

Really need help pls

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

∠1 = 45°

∠2 = 45°

∠3 = 45°

∠4 = 90°

BC = 12

AB = 12

DC = 12

EB = 8.5

DB = 17

EC = 8.5

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Estimate 40% of 128<br> Please help :c
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Step-by-step explanation:

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Read 2 more answers
The entrance hall in Black's family house has a perimeter of 71 2/3 ft.IF it is 9 2/5 ft wide, how long is it?
serious [3.7K]

Answer: 26 13/30 feet

Step-by-step explanation:

The hall is in the shape of a rectangle. The perimeter of a rectangle is:

= 2(length + width)

= 2l + 2w

Since perimeter = 71 2/3 ft and Width = 9 2/5 ft wide, the length will be calculated thus:

Perimeter = 2l + 2w

71⅔ = 2l + 2(9 2/5)

71 2/3 = 2l + (2 × 47/5)

71 2/3 = 2l + 94/5

71 2/3 = 2l + 18 4/5

Collect like terms

2l = 71 2/3 - 18 4/5

2l = 71 10/15 - 18 12/15

2l = 52 13/15

l = (52 13/15 ÷ 2)

l = 793/15 × 1/2

l = 793/30

l = 26 13/30

Therefore, the length is 26 13/30ft

3 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
3 years ago
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