All categories

2 years ago

A fish tank has the dimensions of 18 inches in height, 28 inches long, and 16 inches wide. What is the volume of the fish tank?

Mathematics

2 answers:

crimeas [40]2 years ago

5 0

Answer:

8,064 cubic inches

Step-by-step explanation:

16 times 18 times 28 = 8,064

jek_recluse [69]2 years ago

3 0

Answer:

8064in^2

Step-by-step explanation:

multiply all the conponents together.

Also sorry to ask but I just need one more brainliest to level up.

You might be interested in

A square banquet hall has a 3600m2 area. What is the length of the room?

Assoli18 [71]

The answer should be 10.

8 0

3 years ago

Read 2 more answers

Write the following number in scientific notation. 788,000

Andreyy89

Answer:

7.88 x 10^5 is 788,000 is scientific notation

4 0

1 year ago

According to the school survey, 12% of the students at Rockwood Junior High School speak Spanish. There are 36 students at the s

elixir [45]

Mean=np
36=(0.12)n
n=300
300 students were surveyed.
That's the way I answer in my country but I'm not sure about this solution is correct in your school or not.

7 0

3 years ago

Read 2 more answers

Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th

alexandr1967 [171]

I'm guessing the function is

$f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}$

which, split into partial fractions, is equivalent to

$\dfrac1{x-6}-\dfrac1{x+2}$

Recall that for $|x|$ we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

With some rearranging, we find

$\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n$

valid for $\left|\dfrac x6\right|$ , or $|x|$ , and

$\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

So we have

$f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

$f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)$

$f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n$

Taken together, the power series for $f(x)$ can only converge for $|x|$ , or $-2$ .

6 0

2 years ago

What is the answer for 1/3(16a-8)

zzz [600]

<span> 5 1/3a - 2 2/3

Have a wonderful day</span>

8 0

3 years ago