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NNADVOKAT [17]
3 years ago
15

1) Find the area. *

Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer:

answer is.........

Step-by-step explanation:

bleep* bloop*

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Subtract the following polynomials
Olegator [25]

Answer:

1.  (q² + 8) - (4q² + 1)

Simplify each term.

q²+8−4q²−1

Simplify by adding terms.

−3q²+7

2. (3x + 7x² - 6) - (5x² + x + 9)​

Simplify each term.

3x+7x²−6−5x²−x−9

Simplify by adding terms.

Tap for more steps...

2x²+2x−15

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help me
olganol [36]
Ok so I'm pretty sure you multiply 22.45×5 then multiply 25.45×7 then add your answer
3 0
4 years ago
Predict the next number in the table. cycle: 1,2,3,4,5. people told: 1,3,9,27,?​
nikklg [1K]
The answer is 81 the right Column is multiplying by 3
8 0
3 years ago
What if the diameter of the inner sphere is 1.8 meters. What is the volume of the inflated space?
Alona [7]

Answer:

Volume is 3.05m³

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, sphere

Step one

The formula for the volume of a sphere is expressed as

V=4/3πr³

Step two

Given data

Diameter d = 1.8m

Radius r = d/2= 1.8/2= 0.9m

Step three

Substituting our given data we have

V= 4/3*3.142*0.9³

V= 4/3*3.142*0.729

V= 9.162/3

V=3.05m³

4 0
3 years ago
Find the area and perimeter of the shaded region. Stuck on this one can someone help me
alekssr [168]

Answer:

perimeter-

perimeter outer rectangle = 2 (l+b)

=2×8+9

= 2×17

2×17 =34 cm sq.

perimeter of inner rectangle = 2 (l+b)

= 2×5+3

=2× 8

= 16 cm sq.

perimeter of shaded portion= 34 - 16

= 18 cm sq.

area-

<em>area</em><em> </em><em>of</em><em> </em><em> </em><em>inner</em><em> </em> rectangle =l×b

l×b = 3×5

3×5=15

15 cm sq.

area of outer rectangle =l×b

l×b= 9×8

9×8= 72

72 cm sq.

area of shaded portion = 72 -15 =57 cm sq.

hey there! In second method i have done first area of inner rectangle but you have to do first area of outer rectangle...

hope it helps you....

3 0
3 years ago
Read 2 more answers
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