Answer:
2/9 boxes.
Step-by-step explanation:
6 / 1 / 3 = 4 / b
Cross multiply the two
6b = 4/3
Multiply 1/6 on each side
B = 4 /18
It can be reduced to 2/9.
Feel free to let me know if you need more help! :)
Answer:
100
Step-by-step explanation:
please___________________
Hello from MrBillDoesMath!
Answer:
Choice C, sqrt(3-x)
Discussion:
Have no fear, MBill is here!
The quotient is
sqrt (9-x^2) / sqrt( 3+x) = => as sqrt(a)/sqrt(b) = sqrt(a/b), b <> 0
sqrt ( (9-x^2)/( 3+x) ) = => as 9 - x^2 = (3-x) * (3+x)
sqrt ( (3-x)(3+x) /(3+x) ) = => cancel (3+x) from num. and denom.
sqrt( 3-x)
This is Choice C
Note the domain restriction -3 < x < = 3 guarantees that division by zero can't happen.
Thank you,
MrB
Hello!
As we are looking for the opposite side and hypotenuse, we will use the sine.
sin30=1/2
This gives us the equation below.
1/2= 5/x
1/2x=5
x=10
Therefore, x=10.
I hope this helps!
